我尝试了多个版本并阅读了几个相关的答案,但我仍然无法弄清楚为什么Struts没有填充我的Action属性user
。
这是我的ajax电话
function save_new_user() {
var user =
{ username: $('#new_user_username').val(),
email: $('#new_user_email').val(),
password: $('#new_user_password').val()
};
user_json = JSON.stringify(user);
console.log(user_json);
var data = {'user': user_json};
$.ajax({
type : 'GET',
url : 'SaveNewUser',
data: data,
dataType : "json",
contentType: 'application/json',
success : function(data, textStatus, jqXHR) {
if(data) {
}
},
});
}
顺便说一下,在控制台中打印它
{"username":"dd","email":"ff","password":"gg"}
我的Action类(带注释),(我没有修改struts2-json-plugin-2.3.24.1中的json-default
拦截器)
package coproject.cpweb.actions;
import org.apache.struts2.convention.annotation.Action;
import org.apache.struts2.convention.annotation.ParentPackage;
import org.apache.struts2.convention.annotation.Result;
import org.apache.struts2.convention.annotation.Results;
import com.opensymphony.xwork2.ActionSupport;
import coproject.cpweb.utils.db.entities.UserDum;
import coproject.cpweb.utils.db.services.DbServicesImp;
@Action("SaveNewUser")
@ParentPackage("json-default")
@Results({
@Result(name="success", type="json"),
@Result(name="input", location="/views/error.jsp")
})
public class SaveNewUser extends ActionSupport{
private static final long serialVersionUID = 1L;
/* Services */
DbServicesImp dbServices;
public DbServicesImp getDbServices() {
return dbServices;
}
public void setDbServices(DbServicesImp dbServices) {
this.dbServices = dbServices;
}
/* Input Json */
private UserDum user = new UserDum();
public UserDum getUser() {
return user;
}
public void setUser(UserDum user) {
this.user = user;
}
/* Execute */
public String execute() throws Exception {
// dbServices.saveUser(user);
System.out.println(user.getUsername());
return "SUCCESS";
}
}
UserDum
实体是
package coproject.cpweb.utils.db.entities;
public class UserDum {
private String username;
private String email;
private String password;
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
}
但是,当请求到达时,struts-json-plugin的json
拦截器尝试设置“user”时会出现异常。
feb 04, 2016 12:20:14 PM com.opensymphony.xwork2.interceptor.ParametersInterceptor error
SEVERE: Developer Notification (set struts.devMode to false to disable this message):
Unexpected Exception caught setting 'user' on 'class coproject.cpweb.actions.SaveNewUser: Error setting expression 'user' with val
ue ['{"username":"dd","email":"ff","password":"gg"}', ]
feb 04, 2016 12:20:14 PM com.opensymphony.xwork2.util.LocalizedTextUtil warn
WARNING: Missing key [invalid.fieldvalue.user] in bundles [[org/apache/struts2/struts-messages, com/opensymphony/xwork2/xwork-mess
ages]]!
可能出现错误的任何线索?
答案 0 :(得分:2)
扩展json-default
包不会将json
拦截器设置为拦截器的defaultStack
,它只是定义了这样的拦截器。
在interceptorRefs
注释中使用@Action
设置json
拦截器,defaultStack
设置为操作。
@Action(value="SaveNewUser",
interceptorRefs={ @InterceptorRef("json"),
@InterceptorRef("defaultStack") })
或者在类级@InterceptorRefs
将拦截器应用于该类中定义的所有操作。
@InterceptorRefs({
@InterceptorRef("json"),
@InterceptorRef("defaultStack")
})