Question

我正在尝试修改react-router-redux的示例代码。 https://github.com/rackt/react-router-redux/blob/master/examples/basic/components/Home.js

这是我的Home.js

class Home extends Component {
    onSubmit(props) {
        this.props.routeActions.push('/foo');    
    }
}

我也有mapDispatchToProps。

function mapDispatchToProps(dispatch){
    return bindActionCreators({ routeActions },dispatch);
}

当我调用onSubmit函数时，我收到错误

Uncaught TypeError: this.props.routeActions.push is not a function

如果我在onSubmit中删除this.props，则URL中的键已更改，但它仍在同一页面上。从localhost:8080/#/?_k=iwio19到localhost:8080/#/?_k=ldn1ew

任何人都知道如何修复它？欣赏它。

Answer 1

我不认为routeActions被传递为props。你想要做的是：

import { routeActions } from 'react-router-redux'

this.props.dispatch(routeActions.push('/foo'));

Answer 2

在评论中提供一个更明确的答案和我自己的问题的答案。

是的，你可以做到

import { routeActions } from 'react-router-redux'

this.props.dispatch(routeActions.push('/foo));

但是正如我所提到的，mapDispatchToProps会覆盖它。要解决此问题，您可以像这样绑定routeActions：

import { bindActionCreators } from 'redux'
import { routeActions } from 'react-router-redux'

function mapDispatchToProps(dispatch) {
    return {
        routeActions: bindActionCreators(routeActions, dispatch),
    }
}

export default connect(null, mapDispatchToProps)(YourComponent)

现在你可以：this.props.routeActions.push('/foo')

仅供参考，这可以做得更整洁

function mapDispatchToProps(dispatch) {
    return {
        ...bindActions({routeActions, anotherAction}, dispatch)
    }
}

Answer 3

至于react-router-redux v4：

import { push } from 'react-router-redux';

export class ExampleContainer extends React.Component {
  static propTypes = {
    changeRoute: React.PropTypes.func,
  };

  function mapDispatchToProps(dispatch) {
    return {
      changeRoute: (url) => dispatch(push(url)),
      dispatch,
    };
  }
}

export default connect(null, mapDispatchToProps)(ExampleContainer);

然后：

this.props.changeRoute('/foo');

Answer 4

我能够通过这样做来实现它

import { connect } from 'react-redux'
import { bindActionCreators } from 'redux'
import { routeActions } from 'react-router-redux'

export const Cmpt = React.createClass({ //code })

function mapDispatchToProps(dispatch) {
  return bindActionCreators({
    push: routeActions.push,
    //all your other action creators here
  }, dispatch)
}

export const CmptContainer = connect({}, mapDispatchToProps)(Cmpt)

然后你可以使用push via props this.props.push('some/cool/route')

Answer 5

更简洁

对于这些示例，我会像这样讨论mapDispatchToProps函数：

<强> bindActionDispatchers.js

NSOrderedDescending

<强> Foo.js

import { bindActionCreators } from 'redux'

/** curries mapDispatchToProps with bindActionCreators to simplify React action dispatchers. */
export default function bindActionDispatchers(actionCreators) {
  if(typeof actionCreators === 'function')
    return (dispatch, ownProps) => bindActionCreators(actionCreators(ownProps), dispatch)
  return dispatch => bindActionCreators(actionCreators, dispatch)
}

我把它打包成一个轻量级的npm包bind-action-dispatchers，包含单元测试和健全性检查。要使用此版本安装：

<强> import React from 'react' import bindActionDispatchers from './bindActionDispatchers' import { routeActions } from 'react-router-redux' import * as appActions from './actions' const Foo = ({ routeActions ...appActions }) => ( <div> <button onClick={routeActions.push('/route')}>Route</button> <button onClick={appActions.hello('world')}>Hello</button> </div> ) export default connect(null, bindActionDispatchers({ routeActions, ...appActions }))(Foo)

并导入函数：

<强> npm i -S bind-action-dispatchers

如何使用react-router-redux routeActions？

5 个答案:

更简洁