Question

如果输入日期在下面给出，那么日期输出应该是给定的

我希望sas宏代码检查输入中的缺失日期

    1.-MMM-YYYY = 01-MMM-YYYY
    --YYYY    = 01-JAN-YYYY 
    DD--YYYY  = DD-JAN-YYYY 
    DD-MMM-   = DD-MMM-0000

Answer 1

Peeyush，如果您在问题中列出的列表已完成，则下面的代码段是获取所需结果的简单方法。我放了一个宏和非宏if-then语句来处理它。

 data inputss;
       input in  $  ;
       cards;
    -MMM-YYYY 
    --YYYY    
    DD--YYYY  
    DD-MMM-   
    ;

data result;
   set inputs;
if in = '-MMM-YYY' then Date_Output = '01-MMM-YYYY';
else if in = '--YYYY' then Date_Output  = '01-JAN-YYYY' ;
else if in = 'DD--YYYY' then Date_Output  = 'DD-JAN-YYYY' ;
else if in = 'DD-MMM-' then Date_Output   = 'DD-MMM-0000';
run;



%macro checkmiss;
    %if  in = '-MMM-YYY' %THEN Date_Output = '01-MMM-YYYY';
    %else %if  in = '--YYYY' %THEN Date_Output  = '01-JAN-YYYY' ;
    %else %if  in = 'DD--YYYY' %THEN Date_Output  = 'DD-JAN-YYYY' ;
    %else %if  in = 'DD-MMM-' %THEN Date_Output   = 'DD-MMM-0000';
run;
%mend checkmiss;
%checkmiss;

Answer 2

我创建了一个数据集，其中包含缺少日，月和年的所有可能情况。下面的datastep解决了所有可能性以及如何处理它们以您请求的格式创建结果变量new_bdate。

data have; 
  input birthdate $20.; 
   datalines4;
  -JAN-1975 
  --1977 
  02--1978 
  03-JAN- 
  01-JAN-1980
  03--
  -JAN-
;;;;
run;

data haha2(Keep = birthdate new_bdate);
  set have;  
   format day $2. month $3. Year $4. New_bdate $11.;
   call scan(birthdate, 1, First_Pos, First_Length);
   First_Word = substrn(birthdate, First_Pos, First_Length);
   call scan(birthdate, -1, Last_Pos, Last_Length);
   Last_Word = substrn(birthdate, Last_Pos, Last_Length);
   if length(birthdate) = 11 then length1 = 'Y';
  else length1 = 'N';

   if length1 = 'Y' then do;
      Day = substr(birthdate,1,2);
      Month = substr(birthdate,4,3);
      Year = substr(birthdate,8,4);
   end;
   else if length1 = 'N' then do;
     if (First_Pos = '1' and Last_Length = '2')  then do 
              Day = First_Word;
              Month = 'JAN';
              Year = '0000';
        end;
      else if (First_Pos = '1' and Last_Length = '3')  then do 
              Day = First_Word;
              Month = Last_Word;
              Year = '0000';
        end;
     else if (First_Pos = '1' and Last_Length = '4')  then do 
              Day = First_Word;
              Month = 'JAN';
              Year = Last_Word;
        end;
   if (First_Pos = '2' and Last_Length = '3')  then do 
              Day = '01';
              Month = First_Word;
              Year = '0000';
        end;
      else if (First_Pos = '2' and Last_Length = '4')  then do 
              Day = '01';
              Month = First_Word;
              Year = Last_Word;
        end;
     else if (First_Pos = '3' and Last_Length = '4')  then do 
              Day = '01';
              Month = 'JAN';
              Year = Last_Word;
        end;
    end;
New_bdate = Day||'-'||Month||'-'||Year;
run;

用于检查缺少日期的sas宏代码

2 个答案: