如果没有设置GET变量，如何在页面上显示内容？

时间：2016-02-04 05:11:39

标签： php html mysql css

我目前有这样的页面，www.page.com / bars.php？monday，www.page.com / bars？php？Tuesday等。根据设置的日期，我会显示不同的内容。我是这样做的：

        if (isset($_GET['monday']) && empty($_GET['monday'])) {
            $query = "SELECT * FROM `bars_mon`";
            $result = mysql_query($query) or die("no query");

            $objects = array();
            while($row = mysql_fetch_assoc($result)) {
                $objects[] = $row;
            }

            foreach($objects as $object) {

                echo
                '<div class="bars-loc-cont">
                    <a href="' . $object['link'] . '"><img src="' . $object['img_link'] . '" /></a>
                    <div class="bars-info">
                        <a href="' . $object['link'] . '"><p class="bars-title">' . $object['title'] . '</p></a>
                        <p class="bars-line-1">' . $object['line_1'] . '</p>
                        <p class="bars-line-2">' . $object['line_2'] . '</p>
                        <p class="bars-line-3">' . $object['line_3'] . '</p>
                        <p class="bars-line-4">' . $object['line_4'] . '</p>
                        <p class="bars-line-5">' . $object['line_5'] . '</p>
                    </div>
                </div>';

            }
        } else if (isset($_GET['tuesday']) && empty($_GET['tuesday'])) {
            $query = "SELECT * FROM `bars_tues`";
            $result = mysql_query($query) or die("no query");

            $objects = array();
            while($row = mysql_fetch_assoc($result)) {
                $objects[] = $row;
            }

            foreach($objects as $object) {

                echo
                '<div class="bars-loc-cont">
                    <a href="' . $object['link'] . '"><img src="' . $object['img_link'] . '" /></a>
                    <div class="bars-info">
                        <a href="' . $object['link'] . '"><p class="bars-title">' . $object['title'] . '</p></a>
                        <p class="bars-line-1">' . $object['line_1'] . '</p>
                        <p class="bars-line-2">' . $object['line_2'] . '</p>
                        <p class="bars-line-3">' . $object['line_3'] . '</p>
                        <p class="bars-line-4">' . $object['line_4'] . '</p>
                        <p class="bars-line-5">' . $object['line_5'] . '</p>
                    </div>
                </div>';

            }
        } else if (isset($_GET['wednesday']) && empty($_GET['wednesday'])) {
            $query = "SELECT * FROM `bars_wed`";
            $result = mysql_query($query) or die("no query");

            $objects = array();
            while($row = mysql_fetch_assoc($result)) {
                $objects[] = $row;
            }

            foreach($objects as $object) {

                echo
                '<div class="bars-loc-cont">
                    <a href="' . $object['link'] . '"><img src="' . $object['img_link'] . '" /></a>
                    <div class="bars-info">
                        <a href="' . $object['link'] . '"><p class="bars-title">' . $object['title'] . '</p></a>
                        <p class="bars-line-1">' . $object['line_1'] . '</p>
                        <p class="bars-line-2">' . $object['line_2'] . '</p>
                        <p class="bars-line-3">' . $object['line_3'] . '</p>
                        <p class="bars-line-4">' . $object['line_4'] . '</p>
                        <p class="bars-line-5">' . $object['line_5'] . '</p>
                    </div>
                </div>';

            }
        } else if (isset($_GET['thursday']) && empty($_GET['thursday'])) {
            $query = "SELECT * FROM `bars_thurs`";
            $result = mysql_query($query) or die("no query");

            $objects = array();
            while($row = mysql_fetch_assoc($result)) {
                $objects[] = $row;
            }

            foreach($objects as $object) {

                echo
                '<div class="bars-loc-cont">
                    <a href="' . $object['link'] . '"><img src="' . $object['img_link'] . '" /></a>
                    <div class="bars-info">
                        <a href="' . $object['link'] . '"><p class="bars-title">' . $object['title'] . '</p></a>
                        <p class="bars-line-1">' . $object['line_1'] . '</p>
                        <p class="bars-line-2">' . $object['line_2'] . '</p>
                        <p class="bars-line-3">' . $object['line_3'] . '</p>
                        <p class="bars-line-4">' . $object['line_4'] . '</p>
                        <p class="bars-line-5">' . $object['line_5'] . '</p>
                    </div>
                </div>';

            }
        } else if (isset($_GET['friday']) && empty($_GET['friday'])) {
            $query = "SELECT * FROM `bars_fri`";
            $result = mysql_query($query) or die("no query");

            $objects = array();
            while($row = mysql_fetch_assoc($result)) {
                $objects[] = $row;
            }

            foreach($objects as $object) {

                echo
                '<div class="bars-loc-cont">
                    <a href="' . $object['link'] . '"><img src="' . $object['img_link'] . '" /></a>
                    <div class="bars-info">
                        <a href="' . $object['link'] . '"><p class="bars-title">' . $object['title'] . '</p></a>
                        <p class="bars-line-1">' . $object['line_1'] . '</p>
                        <p class="bars-line-2">' . $object['line_2'] . '</p>
                        <p class="bars-line-3">' . $object['line_3'] . '</p>
                        <p class="bars-line-4">' . $object['line_4'] . '</p>
                        <p class="bars-line-5">' . $object['line_5'] . '</p>
                    </div>
                </div>';

            }
        } else if (isset($_GET['saturday']) && empty($_GET['saturday'])) {
            $query = "SELECT * FROM `bars_sat`";
            $result = mysql_query($query) or die("no query");

            $objects = array();
            while($row = mysql_fetch_assoc($result)) {
                $objects[] = $row;
            }

            foreach($objects as $object) {

                echo
                '<div class="bars-loc-cont">
                    <a href="' . $object['link'] . '"><img src="' . $object['img_link'] . '" /></a>
                    <div class="bars-info">
                        <a href="' . $object['link'] . '"><p class="bars-title">' . $object['title'] . '</p></a>
                        <p class="bars-line-1">' . $object['line_1'] . '</p>
                        <p class="bars-line-2">' . $object['line_2'] . '</p>
                        <p class="bars-line-3">' . $object['line_3'] . '</p>
                        <p class="bars-line-4">' . $object['line_4'] . '</p>
                        <p class="bars-line-5">' . $object['line_5'] . '</p>
                    </div>
                </div>';

            }
        } else if (isset($_GET['sunday']) && empty($_GET['sunday'])) {
            $query = "SELECT * FROM `bars_sun`";
            $result = mysql_query($query) or die("no query");

            $objects = array();
            while($row = mysql_fetch_assoc($result)) {
                $objects[] = $row;
            }

            foreach($objects as $object) {

                echo
                '<div class="bars-loc-cont">
                    <a href="' . $object['link'] . '"><img src="' . $object['img_link'] . '" /></a>
                    <div class="bars-info">
                        <a href="' . $object['link'] . '"><p class="bars-title">' . $object['title'] . '</p></a>
                        <p class="bars-line-1">' . $object['line_1'] . '</p>
                        <p class="bars-line-2">' . $object['line_2'] . '</p>
                        <p class="bars-line-3">' . $object['line_3'] . '</p>
                        <p class="bars-line-4">' . $object['line_4'] . '</p>
                        <p class="bars-line-5">' . $object['line_5'] . '</p>
                    </div>
                </div>';

            }
        }

我想知道的是，当用户只访问www.page.com/bars.php时，我该怎么做才能让我展示一下这样的日子呢？如果我选择一天，我想隐藏bars.php内容并仅显示bars.php？＆＃39; day＆＃39;内容。还有，有什么办法可以缩短这段代码吗？似乎会有更短的方式来做到这一点。

6 个答案:

答案 0 :(得分：2)

网址应该是www.page.com/bars.php?day=tuesday 

<?php
    $day = (isset($_GET['day']) && !empty($_GET['day']))?$_GET['day']:'';
    switch ($day) {
        case "monday":
             $query = "SELECT * FROM `bars_mon`";
            break;
        case "tuesday":
             $query = "SELECT * FROM `bars_tues`";
            break;
        case "wednesday":
            $query = "SELECT * FROM `bars_wed`";
            break;
        case "thursday":
             $query = "SELECT * FROM `bars_thurs`";
            break;
        case "friday":
            $query = "SELECT * FROM `bars_fri`";
            break;
        case "saturday":
            $query = "SELECT * FROM `bars_sat`";
            break;
        case "sunday":
            $query = "SELECT * FROM `bars_sun`";
            break;
        default:
            $query = false;
    }
    if($query) {
        $result = mysql_query($query) or die("no query");
        $objects = array();
        while($row = mysql_fetch_assoc($result)) {
            $objects[] = $row;
        }

        foreach($objects as $object) {
            echo
            '<div class="bars-loc-cont">
                <a href="' . $object['link'] . '"><img src="' . $object['img_link'] . '" /></a>
                <div class="bars-info">
                    <a href="' . $object['link'] . '"><p class="bars-title">' . $object['title'] . '</p></a>
                    <p class="bars-line-1">' . $object['line_1'] . '</p>
                    <p class="bars-line-2">' . $object['line_2'] . '</p>
                    <p class="bars-line-3">' . $object['line_3'] . '</p>
                    <p class="bars-line-4">' . $object['line_4'] . '</p>
                    <p class="bars-line-5">' . $object['line_5'] . '</p>
                </div>
            </div>';

        }
    } else {
        echo 'your other code here';
    }
    ?>

答案 1 :(得分：1)

您需要使用array_keys从$_GET获取密钥。

您将获得第一天的价值。

<强>步骤：

1）检查$_GET是否为空。

2）使用array_keys获取数组的键。

3）创建一个允许的工作日数组。

4）创建另一个多维天数和数据库表数组。

5）其中key为day，value为数据库表名。

6）如果一切正常，请使用day键获取数据库表的名称。

7）这将是数据库表名。

8）如果它不是空的，则完成其余的工作。

<强>代码： 

<?php
$days = isset($_GET) && ! empty($_GET) ? array_keys($_GET) : array();
$day = (current($days)) ? strtolower(current($days)) : '';
$allowedDays = array('monday', 'tuesday', 'wednesday', 'thursday', 'friday', 'saturday', 'sunday'); // Only allowed days.
if (! in_array($day, $allowedDays)) {
  die('incorrect day');
}
$dbTables = array();
$dbTables['monday'] = 'bars_mon';
$dbTables['tuesday'] = 'bars_tues';
$dbTables['wednesday'] = 'bars_wed';
$dbTables['thursday'] = 'bars_thurs';
$dbTables['friday'] = 'bars_fri';
$dbTables['saturday'] = 'bars_sat';
$dbTables['sunday'] = 'bars_sun';
$tableName = isset($dbTables[$day]) ? $dbTables[$day] : '';
if (! empty($tableName)) {
  $query = "SELECT * FROM `" . $tableName . "`";
  // REST OF THE CODE...
}
?>

答案 2 :(得分：0)

这是一个更简单的方法，它允许默认：

使用?day=mon进行呼叫，例如

$days = array(
    "mon", "tue", "wed", "thu", "fri", "sat", "sun",
);

$day = "mon";
if (isset($_GET['day']) && in_array($_GET['day'], $days)) {
    $day = $_GET['day'];
}

$query = "SELECT * FROM `bars_$day`";

$result = mysqli_query($query) or die("no query");

$objects = array();
while($row = mysqli_fetch_assoc($result)) {
    $objects[] = $row;
}

foreach($objects as $object) {
    echo
    '<div class="bars-loc-cont">
        <a href="' . $object['link'] . '"><img src="' . $object['img_link'] . '" /></a>
        <div class="bars-info">
            <a href="' . $object['link'] . '"><p class="bars-title">' . $object['title'] . '</p></a>
            <p class="bars-line-1">' . $object['line_1'] . '</p>
            <p class="bars-line-2">' . $object['line_2'] . '</p>
            <p class="bars-line-3">' . $object['line_3'] . '</p>
            <p class="bars-line-4">' . $object['line_4'] . '</p>
            <p class="bars-line-5">' . $object['line_5'] . '</p>
        </div>
    </div>';

}

未来的一些提示：

  • 说真的，停止使用mysql_ *函数 - 它们已被弃用且不安全。 mysqli_ *更好，但请查看PDO并准备好陈述。
  • 调查错误处理比调用die()更好 - 您希望为用户提供好的错误消息，而不是原始文本
  • 研究将数据逻辑（模型）与表示（视图）分开
  • 当if / else链中的每个分支使用相同的15行代码并且只有一个值变化时，请查看重写代码。现在，如果您向输出中添加新信息，则只需更新一次代码而不是七次。

答案 3 :(得分：0)

我认为你必须通过星期一或任何其他日子，如：

www.page.com/bars.php?day=monday

then

you can access like:  $_GET['day']

答案 4 :(得分：0)

在页面开头，检查if (empty($_GET)) { // no data passed by get, Set your get to your current day or any other day $current_day = date('l'); $_GET[$current_day] = /**set it to what you want*/; } 是否为空

log (5.5)

答案 5 :(得分：0)

你应该这样做：

<?php

# Check if weekday is passed in GET paramater in index `on`
# if not set then get current weekday using PHP date function
# to show current day records instead showing empty page
$day = (isset($_GET['on']) && !empty($_GET['on'])) ? $_GET['on'] : strtolower(date('l'));

$weekdays_and_db_tables = array(
    'sunday' => 'sun',
    'monday' => 'mon',
    'tuesday' => 'tues',
    'wednesday' => 'wed',
    'thursday' => 'thurs',
    'friday' => 'fri',
    'saturday' => 'sat',
);

# Now check if weekdays is correct
if (!isset($weekdays_and_db_tables[$day]) or $weekdays_and_db_tables[$day] == '') {
    die('Invalid weekday!');
}

# SQL Injection can cause here, so beware
# you should migrate all table in one and filter records using an extra column `weekday`
$query = printf("SELECT * FROM `bars_%s`", $weekdays_and_db_tables[$day]);
# instead separate table for each weekdays migrate in one and do:
$query_x = printf("SELECT * FROM `bars_weekdays` WHERE `weekday` = '%s'", $weekdays_and_db_tables[$day]);
$result = mysqli_query($query) or die("no query");

while($object = mysqli_fetch_assoc($result)) {
    echo <<<HTML
<div class="bars-loc-cont">
    <a href="{$object['link']}"><img src="{$object['img_link']}" /></a>
    <div class="bars-info">
        <a href="{$object['link']}"><p class="bars-title">{$object['title']}</p></a>
        <p class="bars-line-1">{$object['line_1']}</p>
        <p class="bars-line-2">{$object['line_2']}</p>
        <p class="bars-line-3">{$object['line_3']}</p>
        <p class="bars-line-4">{$object['line_4']}</p>
        <p class="bars-line-5">{$object['line_5']}</p>
    </div>
</div>
HTML;
}
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