很难描述我想知道的内容。粗略地说，它将每组行选择成一行“＃34;
请参阅链接图片。
谢谢！
click here for an image: SQL Server, select each group of rows into a sing row
dbo.SourceTable
group column1 column2
------------------------
A A1 AA1
A A2 AA2
A A3 AA3
A A4 AA4
A A5 AA5
B B1 BB1
B B2 BB2
B B3 BB3
B B4 BB4
B B5 BB5
C C1 CC1
C C2 CC2
C C3 CC3
C C4 CC4
C C5 CC5
D D1 DD1
D D2 DD2
D D3 DD3
D D4 DD4
D D5 DD5
期望的结果：
group result1 result2 result3 result4 result5 result6 result7 result8 result9 result10
A A1 AA1 A2 AA2 A3 AA3 A4 AA4 A5 AA5
B B1 BB1 B2 BB2 B3 BB3 B4 BB4 B5 BB5
C C1 CC1 C2 CC2 C3 CC3 C4 CC4 C5 CC5
D D1 DD1 D2 DD2 D3 DD3 D4 DD4 D5 DD5
答案 0 :(得分：2)
没有简单的方法来转动多个列。但有一个诀窍：
您可以连接两个列并对连接值执行操作。甚至更好：您可以让连接的值看起来像XML（而不将其转换为真正的XML ）并对此进行调整。这种方法可以轻松获得值 typesafe 。
但我必须承认：打字很多： - ）
DECLARE @tbl TABLE(groupColumn VARCHAR(1),Column1 VARCHAR(2),Column2 VARCHAR(3));
INSERT INTO @tbl VALUES
('A','A1','AA1')
,('A','A2','AA2')
,('A','A3','AA3')
,('A','A4','AA4')
,('A','A5','AA5')
,('B','B1','BB1')
,('B','B2','BB2')
,('B','B3','BB3')
,('B','B4','BB4')
,('B','B5','BB5')
,('C','C1','CC1')
,('C','C2','CC2')
,('C','C3','CC3')
,('C','C4','CC4')
,('C','C5','CC5')
,('D','D1','DD1')
,('D','D2','DD2')
,('D','D3','DD3')
,('D','D4','DD4')
,('D','D5','DD5');
SELECT p.groupColumn
,casted.Xml1.value('/x[1]','varchar(max)') AS Result1a
,casted.Xml1.value('/x[2]','varchar(max)') AS Result1b
,casted.Xml2.value('/x[1]','varchar(max)') AS Result2a
,casted.Xml2.value('/x[2]','varchar(max)') AS Result2b
,casted.Xml3.value('/x[1]','varchar(max)') AS Result3a
,casted.Xml3.value('/x[2]','varchar(max)') AS Result3b
,casted.Xml4.value('/x[1]','varchar(max)') AS Result4a
,casted.Xml4.value('/x[2]','varchar(max)') AS Result4b
,casted.Xml5.value('/x[1]','varchar(max)') AS Result5a
,casted.Xml5.value('/x[2]','varchar(max)') AS Result5b
,casted.Xml6.value('/x[1]','varchar(max)') AS Result6a
,casted.Xml6.value('/x[2]','varchar(max)') AS Result6b
,casted.Xml7.value('/x[1]','varchar(max)') AS Result7a
,casted.Xml7.value('/x[2]','varchar(max)') AS Result7b
,casted.Xml8.value('/x[1]','varchar(max)') AS Result8a
,casted.Xml8.value('/x[2]','varchar(max)') AS Result8b
,casted.Xml9.value('/x[1]','varchar(max)') AS Result9a
,casted.Xml9.value('/x[2]','varchar(max)') AS Result9b
,casted.Xml10.value('/x[1]','varchar(max)') AS Result10a
,casted.Xml10.value('/x[2]','varchar(max)') AS Result10b
FROM
(
SELECT groupColumn
,'result' + CAST(ROW_NUMBER() OVER(PARTITION BY groupColumn ORDER BY Column1,Column2) AS VARCHAR(MAX)) AS ColumnName
,'<x>' + Column1 + '</x><x>' + Column2 + '</x>' AS PivotColumn
FROM @tbl
) AS pvt
PIVOT
(
MIN(PivotColumn) FOR ColumnName IN(result1,result2,result3,result4,result5,result6,result7,result8,result9,result10)
) AS p
OUTER APPLY
(
SELECT CAST(p.result1 AS XML) AS Xml1
,CAST(p.result2 AS XML) AS Xml2
,CAST(p.result3 AS XML) AS Xml3
,CAST(p.result4 AS XML) AS Xml4
,CAST(p.result5 AS XML) AS Xml5
,CAST(p.result6 AS XML) AS Xml6
,CAST(p.result7 AS XML) AS Xml7
,CAST(p.result8 AS XML) AS Xml8
,CAST(p.result9 AS XML) AS Xml9
,CAST(p.result10 AS XML) AS Xml10
) AS casted
结果
groupColumn Result1a Result1b Result2a Result2b Result3a Result3b Result4a Result4b Result5a Result5b Result6a Result6b Result7a Result7b Result8a Result8b Result9a Result9b Result10a Result10b
A A1 AA1 A2 AA2 A3 AA3 A4 AA4 A5 AA5 NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL
B B1 BB1 B2 BB2 B3 BB3 B4 BB4 B5 BB5 NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL
C C1 CC1 C2 CC2 C3 CC3 C4 CC4 C5 CC5 NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL
D D1 DD1 D2 DD2 D3 DD3 D4 DD4 D5 DD5 NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL
答案 1 :(得分：1)
这是这样做的一种方式：
CREATE TABLE #tt(id INT IDENTITY(1,1),[group] VARCHAR(16),[column1] VARCHAR(16),[column2] VARCHAR(16))
INSERT INTO #tt([group],[column1],[column2])VALUES
('A','A1','AA1'),
('A','A2','AA2'),
('A','A3','AA3'),
('A','A4','AA4'),
('A','A5','AA5'),
('B','B1','BB1'),
('B','B2','BB2'),
('B','B3','BB3'),
('B','B4','BB4'),
('B','B5','BB5'),
('C','C1','CC1'),
('C','C2','CC2'),
('C','C3','CC3'),
('C','C4','CC4'),
('C','C5','CC5'),
('D','D1','DD1'),
('D','D2','DD2'),
('D','D3','DD3'),
('D','D4','DD4'),
('D','D5','DD5');
;WITH group_order AS (
SELECT
*,
group_order_id=ROW_NUMBER() OVER (PARTITION BY [group] ORDER BY id)
FROM
#tt
)
SELECT
[group],
result1=MAX(CASE WHEN group_order_id=1 THEN [column1] END),
result2=MAX(CASE WHEN group_order_id=1 THEN [column2] END),
result3=MAX(CASE WHEN group_order_id=2 THEN [column1] END),
result4=MAX(CASE WHEN group_order_id=2 THEN [column2] END),
result5=MAX(CASE WHEN group_order_id=3 THEN [column1] END),
result6=MAX(CASE WHEN group_order_id=3 THEN [column2] END),
result7=MAX(CASE WHEN group_order_id=4 THEN [column1] END),
result8=MAX(CASE WHEN group_order_id=4 THEN [column2] END),
result9=MAX(CASE WHEN group_order_id=5 THEN [column1] END),
result10=MAX(CASE WHEN group_order_id=5 THEN [column2] END)
FROM
group_order
GROUP BY
[group];
DROP TABLE #tt;
结果：
+-------+---------+---------+---------+---------+---------+---------+---------+---------+---------+----------+
| group | result1 | result2 | result3 | result4 | result5 | result6 | result7 | result8 | result9 | result10 |
+-------+---------+---------+---------+---------+---------+---------+---------+---------+---------+----------+
| A | A1 | AA1 | A2 | AA2 | A3 | AA3 | A4 | AA4 | A5 | AA5 |
| B | B1 | BB1 | B2 | BB2 | B3 | BB3 | B4 | BB4 | B5 | BB5 |
| C | C1 | CC1 | C2 | CC2 | C3 | CC3 | C4 | CC4 | C5 | CC5 |
| D | D1 | DD1 | D2 | DD2 | D3 | DD3 | D4 | DD4 | D5 | DD5 |
+-------+---------+---------+---------+---------+---------+---------+---------+---------+---------+----------+