Question

我有这个PHP邮件，到目前为止工作，但当我收到邮件我没有从联系表格中获得名称，电子邮件或电话信息，我只是得到主题和消息。我怎么能解决这个问题？非常感谢。

<?php
$name       = @trim(stripslashes($_POST['name'])); 
$from       = @trim(stripslashes($_POST['email'])); 
$tel       = @trim(stripslashes($_POST['tel'])); 
$subject    = @trim(stripslashes($_POST['subject'])); 
$message    = @trim(stripslashes($_POST['message'])); 
$to         = 'example@example.com';//replace with your email


$headers = "MIME-Version: 1.0";
$headers .= "Content-type: text/plain; charset=iso-8859-1";
$headers .= "From: {$name} <{$from}>";
$headers .= "Reply-To: <{$from}>";
$headers .= "Subject: {$subject}";
$headers .= "X-Mailer: PHP/".phpversion();

mail($to, $subject, $message, $headers);

die;

?>

Answer 1

您在电子邮件的邮件正文中不包含$message以外的任何内容。有关详细信息，请参阅this reference on mail()。

我提供了一个示例，说明如何在下面的消息中包含其他变量：

<?php
$name       = @trim(stripslashes($_POST['name'])); 
$from       = @trim(stripslashes($_POST['email'])); 
$tel       = @trim(stripslashes($_POST['tel'])); 
$subject    = @trim(stripslashes($_POST['subject'])); 
$message    = @trim(stripslashes($_POST['message'])); 
$to         = 'yorchdiazc@hotmail.com';//replace with your email

$headers = "MIME-Version: 1.0";
$headers .= "Content-type: text/plain; charset=iso-8859-1";
$headers .= "From: {$name} <{$from}>";
$headers .= "Reply-To: <{$from}>";
$headers .= "Subject: {$subject}";
$headers .= "X-Mailer: PHP/".phpversion();

// add name, email, tel to message - choose whichever markup you wish
$message_body = "
Name = " . $name . "<br>
Email = " . $email . "<br>
Tel = " . $tel . "<br>
Message = " . $message;

mail($to, $subject, $message_body, $headers);

die;

?>

简单的PHP邮件问题

1 个答案: