将列作为单个记录的行返回

Question

我已经阅读了本网站以及其他有关使用PIVOT，UNPIVOT，UNION和CROSS JOIN的帖子，但我似乎无法得到我想要的结果。

我的表格如下：

EmployeeName    Salary  Address             City        State   Zip     AdditionalDetails
=========================================================================================
Doe, John       400000  111 Jackson Ave     Nowhere     CA      99999   Reliable 
Blow, Joe       300000  222 Johnson St      Somewhere   ME      00000   Always late

我试图展示的内容如下：

EmployeeName        Doe, John
Salary              400000
Address             111 Jackson Ave
City                Nowhere
State               CA
Zip                 99999
AdditionalDetails   Reliable

我最接近的是如下使用UNPIVOT，但问题是两列是换位的，我需要交换它们，虽然我不知道该怎么做。

SELECT *
FROM
(
    SELECT EmployeeName, Salary, Address, City, State, Zip, AdditionalDetails
    FROM EmployeeDetails
    WHERE EmployeeDetails.EmployeeID=@EmployeeID
) AS SourceTable
UNPIVOT
(
    Value FOR Header IN
    (EmployeeName, Salary, Address, City, State, Zip, AdditionalDetails)
) AS UnpivotTable

所以我得到的是：

Value           Header
Doe, John       EmployeeName
400000          Salary
111 Jackson Ave Address
Nowhere         City
CA              State
99999           Zip
Reliable        AdditionalDetails

如何在需要时显示数据？我首先要说的是，每次使用此查询只返回一条员工记录。我将此数据附加到CSV中，并且请求以这种方式显示员工记录。

Answer 1

你快到了：

您拥有的代码是：

SELECT *
FROM
(
    SELECT EmployeeName, Salary, Address, City, State, Zip, AdditionalDetails
    FROM EmployeeDetails
    WHERE EmployeeDetails.EmployeeID=@EmployeeID
) AS SourceTable
UNPIVOT
(
    Value FOR Header IN
    (EmployeeName, Salary, Address, City, State, Zip, AdditionalDetails)
) AS UnpivotTable

你应该：

SELECT Header, Value
FROM
(
    SELECT EmployeeName, Salary, Address, City, State, Zip, AdditionalDetails
    FROM EmployeeDetails
    WHERE EmployeeDetails.EmployeeID=@EmployeeID
) AS SourceTable
UNPIVOT
(
    Value FOR Header IN
    (EmployeeName, Salary, Address, City, State, Zip, AdditionalDetails)
) AS UnpivotTable

结果：