我的目标是填充mongoosastic搜索中的某些字段,但如果我执行以下代码,它将始终返回
这是代码
var mongoose = require('mongoose');
var Category = require('./category');
var mongoosastic = require('mongoosastic');
var Schema = mongoose.Schema;
var ProductSchema = new Schema({
category: { type: Schema.Types.ObjectId, ref: 'Category', es_schema: Category, es_indexed:true, es_select: 'name'},
name: String,
price: Number,
image: String
});
ProductSchema.plugin(mongoosastic, {
hosts: [
'localhost:9200'
],
populate: [
{path: 'category', select: 'name'}
]
});
module.exports = mongoose.model('Product', ProductSchema);
var mongoose = require('mongoose');
var Schema = mongoose.Schema;
var CategorySchema = new Schema({
name: { type: String, unique: true, lowercase: true}
});
module.exports = mongoose.model('Category', CategorySchema);
api.js
router.post('/search', function(req, res, next) {
console.log(req.body.search_term);
Product.search({
query_string: { query: req.body.search_term }
}, function(err, results) {
if (err) return next(err);
res.json(results);
});
});
我该如何填充mongoosastic中的某个类别?
答案 0 :(得分:0)
您正在使用
#myDiv [class^="col-"] {
}
但代码中的populate: [
{path: 'categories', select: 'name'}
]
为categories
。
您必须使用类别代替
undefined
在模式声明中将键作为类别提到
希望它能解决你的问题。
答案 1 :(得分:-1)
编辑:
类别:{type:Schema.Types.ObjectId,ref:' Category',es_schema:Category,es_indexed:true,es_select:' name'},
=> _category:{type:Schema.Types.ObjectId,ref:' Category' },
并使用populate:.populate(' _category',' name')
希望它会对你有所帮助。