Question

我无法通过AsyncTask（MainActivity innerclass）中的onPostExecute在TextView中设置文本

public class MainActivity  extends Activity {
...
private TextView txt_msg;
...
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);


    txt_msg =  (TextView) findViewById(R.id.txt_msg);
    txt_msg.setText("ON create"); // <-- OK this works

    ...
    ...

    btn = (Button) findViewById(R.id.btn_associa);
    btn.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {
                    String url = "http://myurl.php?a=1&b=2&c=3";
                    MainActivity.SQLAsync dlTask = new MainActivity().new SQLAsync(url);
                    dlTask.execute();
            }
        }
    });

    ...
    ...
    ...


    class SQLAsync extends AsyncTask<URL, Integer, String> {
     private String myurl = "";

        public SQLAsync(String _url) {
            super();
            myurl = _url;
        }

        @Override
        protected void onPreExecute() {
        //empty
        }

        @Override
        protected String doInBackground(URL... urls) {
            InputStream is = null;
            String result = "";
            JSONObject jArray = null;

            try {
                URL url = new URL(myurl);
                HttpURLConnection conn = (HttpURLConnection) url.openConnection();
                conn.setRequestMethod("GET");
                int resp_code = conn.getResponseCode();
                is = new BufferedInputStream(conn.getInputStream());

            } catch (Exception e) {
                Log.e("tag", "Error in http connection " + e.toString());
            }

            try {
                BufferedReader reader = new BufferedReader(new InputStreamReader(is, "iso-8859-1"), 8);
                StringBuilder sb = new StringBuilder();
                String line = null;
                while (reader.readLine() != null) {
                    line = reader.readLine();
                    sb.append(line + "\n");
                }
                is.close();
                result = sb.toString();


            } catch (Exception e) {
                Log.e("tag", "Error converting result " + e.toString());
            }
            return result;
        }

        protected void onProgressUpdate(Integer... progress) {
        //empty
        }

        @Override
        protected void onPostExecute(String s) {
            String result = s;
            Log.i("davide", "String post execute " + s.toString());

            if (txt_msg!=null) // <-- THIS IS NULL
                txt_msg.setText("MESSAGGIO DI SISTEMA"); 

                ...
                ...
                ...

        }
    }

}

我已经检查了其他类似问题的帖子，但是他们在AsyncTask中有TextView定义，在我的情况下，我无法理解错误。

Answer 1

您正在从SQLAsync课程的新实例创建新的MainActivity，而不是现有的实例。

变化：

MainActivity.SQLAsync dlTask = new MainActivity().new SQLAsync(url);

要：

SQLAsync dlTask = new SQLAsync(url);

Answer 2

而不是

MainActivity.SQLAsync dlTask = new MainActivity().new SQLAsync(url);

初始化如下：

SQLAsync dlTask = new SQLAsync(url);

Android无法从onPostExecute更新TextView

2 个答案: