Question

对于模糊的标题感到抱歉，不确定如何描述它

基本上我有一张这样的桌子（汽车由^^隔开）

id| cars 
-------------------------
 1|car1 ^^ car2 ^^ car3
 2|car2 ^^ car3
 3|car1
 4|car1 ^^ car 2
 5|car3

基本上我想列出所有与他们匹配的id的汽车

car |id
-------------
car1|1,3,4
car2|1,2,4
car3|1,2,5

在mySQL中可以做到这一点吗？它的查询是什么？

非常感谢任何帮助！

Answer 1

这应该有效。我正在使用表变量“@Cars”来填充我的结果，但是，您可以将其替换为数据库中的实际表名。

--Table Defination:
    DECLARE @Cars TABLE
    (ID   INT IDENTITY,
     Cars VARCHAR(255)
    );
    INSERT INTO @Cars(Cars)
    VALUES('car1 ^^ car2 ^^ car3');
    INSERT INTO @Cars(Cars)
    VALUES('car2 ^^ car3');
    INSERT INTO @Cars(Cars)
    VALUES('car1');
    INSERT INTO @Cars(Cars)
    VALUES('car1 ^^ car2');
    INSERT INTO @Cars(Cars)
    VALUES('car3');

--SQL
    SELECT distinct Cars, STUFF(
                (
                    SELECT ', '+CAST([id] AS NVARCHAR(256))
                    FROM
                    (
                        SELECT A.id,
                               LTRIM(RTRIM(Split.a.value('.', 'VARCHAR(100)'))) AS Cars
                        FROM
                        (
                            SELECT ID,
                                   CAST('<M>'+REPLACE(Cars, '^^', '</M><M>')+'</M>' AS XML) AS String
                            FROM @Cars
                        ) AS A
                        CROSS APPLY String.nodes('/M') AS Split(a)
                    ) T1
                    WHERE T1.Cars = T2.Cars
                    FOR XML PATH('')
                ), 1, 1, '') AS id
    FROM
    (
        SELECT A.id,
               LTRIM(RTRIM(Split.a.value('.', 'VARCHAR(100)'))) AS Cars
        FROM
        (
            SELECT ID,
                   CAST('<M>'+REPLACE(Cars, '^^', '</M><M>')+'</M>' AS XML) AS String
            FROM @Cars
        ) AS A
        CROSS APPLY String.nodes('/M') AS Split(a)
    ) T2;

mySQL查询显示哪个ID具有特定记录

1 个答案: