我正在进行i18n实施。我有像/:locale/rest/of/route
这样的路由,我想根据加载的语言环境传递字典。在路由配置上这样做会很酷。但我只能考虑在每个容器上这样做。但我主要的不确定性是代码重复。 (在每个容器this.props.dictionary[this.props.route.locale]
)
是否可以避免此代码重复?
这是我的配置文件:
import React from 'react'
import ReactDOM from 'react-dom'
import { Provider } from 'react-redux'
import thunk from 'redux-thunk'
import { Router, Route, IndexRoute, Redirect } from 'react-router'
import createBrowserHistory from 'history/lib/createBrowserHistory'
import { syncReduxAndRouter } from 'redux-simple-router'
import * as containers from './app/app/containers'
import AppUser from './app/app/AppUser'
import AppCompany from './app/app/AppCompany'
import { createStore, applyMiddleware } from 'redux'
import reducers from './app/app/reducers'
const createStoreWithMiddleware = applyMiddleware(
thunk
)(createStore)
const store = createStoreWithMiddleware(reducers)
const history = createBrowserHistory()
syncReduxAndRouter(history, store)
ReactDOM.render(
<Provider store={store}>
<Router history={history}>
<Route path="/:lang" component={AppUser}>
<IndexRoute component={containers.Landing} />
<Route
path="workflow"
component={containers.Workflow} />
<Route
path="register"
component={containers.Register} />
<Route
path="login"
component={containers.Login} />
</Route>
<Redirect from="/" to="/en" />
<Route path="/:lang/company" component={AppCompany}>
<Route
path="inbox"
component={containers.Inbox} />
<Route
path="inbox/:caseId"
component={containers.CaseDetail} />
</Route>
<Redirect from="/company/inbox" to="/en/company/inbox" />
</Router>
</Provider>,
document.getElementById('root')
)
答案 0 :(得分:0)
由于您正在使用redux
,因此您可以在react-redux
组件上使用connect
container
并实施类似的内容并访问带有this.props.currentDictionary
的字典。
function mapStateToProps(state, ownProps) {
return {
currentDictionary: state.dictionary[ownProps.route.locale]
}
}
export default connect(mapStateToProps)(Container);
答案 1 :(得分:0)
最后,最好的模式,所以我不必编辑每个容器就是使用组件Activity
中的属性Intent intent = getIntent();
int k = intent.getIntExtra("idnumber", 1);
功能如下:
createElement
最后在你的index.js或你的路线文件中:
Router