如何删除以下php数组中的null？
任何人都可以帮助我吗？
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""
]
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}
答案 0 :(得分：2)
只需使用true：
open array_filter将任何元素评估为数组中的f。它返回一个新数组。
答案 1 :(得分：2)
array_filter可以从数组中删除空字符串，false值和null：
$entry = array(
0 => 'foo',
1 => false,
2 => -1,
3 => null,
4 => ''
);
print_r(array_filter($entry));
将输出：
Array
(
[0] => foo
[2] => -1
)
您还可以定义自己的过滤器，并使用带有所需过滤功能的回调函数调用array_filter：
function odd($var)
{
// returns whether the input integer is odd
return($var & 1);
}
function even($var)
{
// returns whether the input integer is even
return(!($var & 1));
}
$array1 = array("a"=>1, "b"=>2, "c"=>3, "d"=>4, "e"=>5);
$array2 = array(6, 7, 8, 9, 10, 11, 12);
echo "Odd :\n";
print_r(array_filter($array1, "odd"));
echo "Even:\n";
print_r(array_filter($array2, "even"));
将输出：
Odd :
Array
(
[a] => 1
[c] => 3
[e] => 5
)
Even:
Array
(
[0] => 6
[2] => 8
[4] => 10
[6] => 12
)
答案 2 :(得分：0)
您需要重新搜索并删除每个元素。也许像这样的一些方法（注意 - 我没有测试代码，我不是一个PHP程序员）：
function RemoveNull($array)
{
foreach ($array as $key => $value)
{
if (is_array($value))
{
RemoveNull($value);
}
if ($value == null)
{
unset($array[$key]);
}
}
}