从关注表格最大值(日期)
获取结果引导表
id name
75943 name1
82501 name2
lead_follow_up
id lead_id msg date updated
1 75943 msg1 1438930800 1438884890
2 75943 msg2 1416459600 1415901523
3 82501 msg1 1454713200 1454485087
4 82501 msg1 1439362800 1438564891
使用以下查询我得到结果
$ today_date = mktime(0,0,0,$ mon,$ day-1,$ year);
SELECT * FROM (`lead_follow_up`) LEFT JOIN `leads` ON `leads`.`id` = `lead_follow_up`.`lead_id` WHERE `date` <= $today_date GROUP BY `lead_follow_up`.`lead_id` ORDER BY `lead_follow_up`.`date` DESC
从上面的查询我得到数组$previou
$previou= Array
(
[0] => stdClass Object
(
[id] => 1
[lead_id] => 75943
[date] => 1438930800
[updated_on] => 1438884890
)
[1] => stdClass Object
(
[id] => 2
[lead_id] => 75943
[date] => 1416459600
[updated_on] => 1415901523
),
[2] => stdClass Object
(
[id] => 3
[lead_id] => 75943
[date] => 1416459600
[updated_on] => 1415901523
),....etc
);
foreach($previou as $key => $p):
$q = "SELECT `id` FROM (`lead_follow_up`) WHERE `lead_id` = '".$p->id."' AND `date` > '".$p->date."' ORDER BY `updated_on` DESC ";
if(!$this->db->query($q)){
$previouData[$key] = $p;
$pCount++;
}
endforeach;
我真正希望看到的是像
这样的数据id lead_id name msg
1 75943 name1 msg1
在单个查询中优化此功能的任何帮助