input.txt -
I am Hungry
call the shopping mall
connected drive
我想逐行读取input.txt并将其作为请求发送到服务器,然后分别保存响应。如何逐行读写数据?
我的代码只适用于input.txt中的一个输入(例如:我很饿)。你能帮我多次输入怎么做吗?
请求:
fileInput = os.path.join(scriptPath, "input.txt")
if not os.path.exists(fileInput):
print "error message"
Error_Status = 1
sys.exit(Error_Status)
else:
content = open(fileInput, "r").read()
if len(content):
TEXT_TO_READ["tts_input"] = content
TEXT_TO_READ = json.dumps(TEXT_TO_READ)
else:
print "error message 2"
request = Request()
回应:
res = h.getresponse()
data = """MIME-Version: 1.0
Content-Type: multipart/mixed; boundary=--Nuance_NMSP_vutc5w1XobDdefsYG3wq
""" + res.read()
msg = email.message_from_string(data)
for index, part in enumerate(msg.walk(), start=1):
content_type = part.get_content_type()
payload = part.get_payload()
if content_type == "audio/x-wav" and len(payload):
with open('Sound_File.pcm'.format(index), 'wb') as f_pcm:
f_pcm.write(payload)
elif content_type == "application/json":
with open('TTS_Response.txt'.format(index), 'w') as f_json:
f_json.write(payload)
答案 0 :(得分:1)
为了简单起见,让我们实现你应该发生什么的广泛描述:''我想逐行读取input.txt并将其作为请求发送到服务器,然后分别保存响应。 '':
for line in readLineByLine('input.txt'):
sendAsRequest(line)
saveResponse()
从我可以从你的问题中收集到的内容,你已经基本上有函数sendAsRequest(line)
和saveResponse()
(可能是另一个名字),但你错过了函数readLineByLine('input.txt')
。这是:
def readLineByLine(filename):
with open(filename, 'r') as f: #Use with statement to correctly close the file when you read all the lines.
for line in f: # Use implicit iterator over filehandler to minimize memory used
yield line.strip('\n') #Use generator, to minimize memory used, removing trailing carriage return as it is not part of the command.
答案 1 :(得分:-1)
基本上你可以简单地说:
with open('filename') as f:
for line in f.readlines():
print line
输出将是:
我饿了
致电购物中心
连接驱动器
现在可以在这里阅读有关“with”语句的说明: http://effbot.org/zone/python-with-statement.htm