Question

我有routes.rb

city_section_slug GET        (/:locale)/cities/:city_id/:section(.:format)                  cities#show {:locale=>/ru|en/}
city_subsection_slug GET        (/:locale)/cities/:city_id/:section/:subsection(.:format)      cities#show {:subsection=>/[^\/]*/, :locale=>/ru|en/}

rake显示这些路线

= link_to city_subsection_slug_path(@city,section.alias, subsection.alias)

但是当我尝试创建链接时：

ActionController::RoutingError (No route matches {:controller=>"cities", :action=>"show", :locale=>:ru, :city=>#<City id: 42, name: "City">, :section=>"events", :subsection=>"sobytiya/ya-ochevidets"}):

我遇到了这样的错误：

$data = [
    400 => [
        'name' => 'x',
        'lesson_1' => '10',
        'lesson_2' => '9',
        ...
    ],
    389 => ...
]

我错的任何想法？

Answer 1

#config/routes.rb
resources :cities, only: [] do
  get ":section", action: :show, as: :city_section_slug                #-> url.com/cities/:city_id/:section
  get ":section/*subsection", action: :show, as: :city_subsection_slug #-> url.com/cities/:city_id/:section/:subsection
end

相应的链接：

<%= link_to "x", city_section_slug_path(@city, section.alias) %>
<%= link_to "x", city_subsection_slug_path(@city, section.alias, subsection.alias) %>

<强>通配符

如果您希望将sobytiya/ya-ochevidets发送到subsection路径，那么您最好使用wildcard路径

Answer 2

原因是你对subsection param的约束。您指定它可以是任何内容，只要它不包含/个字符。你的小节确实是因为错误。如果您想允许/个字符，请执行以下操作：

get '/cities/:city/:section/:subsection' => 'cities#show',
       as: 'city_subsection_slug',
       constraints: { :subsection => /^[a-z0-9_\/]+$/ }

最终，你可以使用glob param：

get '/cities/:city/:section/*subsection' => 'cities#show',
       as: 'city_subsection_slug',

为什么Rails不认识路线

2 个答案: