Question

我是论坛的新手，也是编程新手。如果我的问题非常基本，我会提前道歉，但我对此非常陌生，而且我必须在很短的时间内学到很多东西，所以我可能会错过几个概念。

关于我的问题，我有一个方法，它应该检查矩阵是否仍有空格，如果找到则停止。

矩阵已经像这样初始化了（我知道它可以在一行中，但矩阵是在对象的构造函数中创建的）

protected char[][] matJeu = null;
matJeu = new char[10][10];

然后充满了像这样的空间＆＃39; ＆＃39;使用for语句，它可以正常工作

这是方法

public boolean checkIfFull()
{
    boolean full = true;
    for (int i=0;i<matJeu.length || !full;i++)
    {
        for (int j=0;j<matJeu[i].length || !full ;j++)
        {
            if(matJeu[i][j]==' '){
                full = false;
            }
        }
    }
    return full;
}

问题在于当完整布尔值变为false时，for循环不会因为导致ArrayOutOfBounds异常而中断并结束。如果矩阵已满，则只返回true。所以我可能错过了使布尔值打破for循环的正确方法。

提前感谢您的时间。

Answer 1

The conditional part of the loop will cause the loop to continue as long as it returns true.

As soon as full=false is hit, then !full==true, and the conditional statement will always evaluate to true (anything || true == true), essentially putting you in an infinite loop with your current code.

To break your for loop, you need the conditional part to evaluate to false.

I'm not sure what you intend your loops to do, as stopping at the first space character doesn't seem like what you want based on the previous paragraph.

Answer 2

The problem is the or condition on your for loops.

for (int i=0;i<matJeu.length || !full;i++)

Here, the loop is going to continue executing so long as at least one of the conditions is true.

Because i<mathJeu.length is still true, the loop keeps executing, regardless of whether full is true or false.

Instead - what you want is an and condition.

for (int i=0;i<matJeu.length && full;i++)

This will tell it 'keep looping so long as it's below the array length AND we've detected it's still full'.

对于语句

2 个答案: