Question

任何人请每两周用C＃MVC 5日历逻辑帮助我。我已经实施了每周日期。

这是我的每周代码。它正在发挥作用。

var day = (from o in db.Suburbs.AsEnumerable()
    ..etc
    select new 
    {

    DT.DeliveryDay,
}).ToList();


foreach (var temp in day)
{
    if (Type == "weekly")
    {
        int weeklyLogic = ((int)Enum.Parse(typeof(DayOfWeek), temp.DeliveryDay) - (int)today.DayOfWeek + 7) % 7;
        DateTime  nextweeklyLogic = today.AddDays(weeklyLogic);
        Firstweek = nextweeklyLogic;
        int weekly2 = (((int)Enum.Parse(typeof(DayOfWeek), temp.DeliveryDay) - (int)today.DayOfWeek + 7) % 7) + 7;
        DateTime Secondweek = today.AddDays(weekly2);
        int weekly3 = (((int)Enum.Parse(typeof(DayOfWeek), temp.DeliveryDay) - (int)today.DayOfWeek + 7) % 7) + 14;
        DateTime Thirdweek = today.AddDays(weekly3);
        etc..
    }
    else if (Type == "fortnightly")
    {

    }
}

例如，使用Type == "fortnightly"，例如temp.DeliveryDay == "Friday"，然后基于今天（2月2日），我希望输出为：

February 5th (First Friday after today, since temp.DeliveryDay is friday)
February 19th (14 days or fortnight from the first output)
March 4th
etc.

Answer 1

首先 - 您重复所有行为以获取每周日期。我建议你分解你的操作。我看到两个主要部分。

获取今天之后第一个任意日期的日期。
从上面确定的日期获取定期重复日期。

此方法可以处理第一部分，

DateTime FirstDayOfWeekAfter(DateTime day, DayOfWeek dayOfWeek)
{
    // We don't want to return today. 
    day = day.AddDays(1);

    // If the current tested day is the desired day of week, return. 
    if (day.DayOfWeek == dayOfWeek)
    {
        return day;
    }
    // else call again with the next day.
    else
    {
        return FirstDayOfWeekAfter(day, dayOfWeek);
    }
}

这对方法将处理第二部分。我这里有第一种方法，所以当你真正使用它时，没有必要使用（DayOfWeek）。

IEnumerable<DateTime> GetPeriodicDeliveryDates(DateTime today, object dayOfDelivery, int period)
{
    return GetPeriodicDeliveryDates(today, (DayOfWeek)dayOfDelivery, period);
}

IEnumerable<DateTime> GetPeriodicDeliveryDates(DateTime today, DayOfWeek dayOfDelivery, int period)
{
    // Get the date of the first delivery. 
    var firstDelivery = FirstDayOfWeekAfter(today, dayOfDelivery);

    while (true)
    {
        // Infinitely yield dates separated by the supplied period length.
        yield return firstDelivery;
        firstDelivery = firstDelivery.AddDays(period);
    }
}

使用这些方法很简单。每周和每两周一次的可枚举之间的唯一区别是传递到GetPeriodicDeliveryDates()的时期。您确实希望确保不要尝试完全枚举GetPeriodicDeliveryDates() - 它是无限顺序的。

var today = DateTime.Today;
var temp = new { DeliveryDay = "Friday" };

var weekly = GetPeriodicDeliveryDates(today, Enum.Parse(typeof(DayOfWeek), temp.DeliveryDay), 7);
var fortnightly = GetPeriodicDeliveryDates(today, Enum.Parse(typeof(DayOfWeek), temp.DeliveryDay), 14);

weekly.Take(5).ToList().ForEach(x => Console.WriteLine(x));
Console.WriteLine();
fortnightly.Take(5).ToList().ForEach(x => Console.WriteLine(x));

两周一次C＃logic

1 个答案: