Question

我使用谷歌的API客户端与Gmail API进行交互。假设我有一个草稿的不可变ID，我想发送相关的草稿。

我试过了：

service.users().drafts().send(
    userId='me', id=draft_id).execute(http=http)

此处draft_id是我要发送的草稿的ID，http是Http的一个实例，适用于其他请求（因此经过适当的身份验证））。

尝试以上操作后，我得到TypeError：

Traceback (most recent call last):
  File "/Applications/GoogleAppEngineLauncher.app/Contents/Resources/GoogleAppEngine-default.bundle/Contents/Resources/google_appengine/lib/webapp2-2.5.2/webapp2.py", line 570, in dispatch
    return method(*args, **kwargs)
  File "/Users/mgilson/git/spider-web/app/pattern/handlers/ajax/email.py", line 77, in post
    'success': int(client.send_draft(draft_id))
  File "/Users/mgilson/git/spider-web/app/pattern/services/email/gmail.py", line 601, in send_draft
    userId='me', id=draft_id) \
  File "/Users/mgilson/git/spider-web/app/third_party/googleapiclient/discovery.py", line 669, in method
    raise TypeError('Got an unexpected keyword argument "%s"' % name)
TypeError: Got an unexpected keyword argument "id"

文档有Java example，但没有python示例。

我尝试过的其他变体：

service.users().drafts().send(
    userId='me', draftId=draft_id).execute(http=http)

service.users().drafts().send(
    userId='me', draft_id=draft_id).execute(http=http)

service.users().drafts().send(
    userId='me', body={'draft': {'id': draft_id}}).execute(http=http)

最后一个实际上给出了一个不同的错误：

Traceback (most recent call last):
  File "/Applications/GoogleAppEngineLauncher.app/Contents/Resources/GoogleAppEngine-default.bundle/Contents/Resources/google_appengine/lib/webapp2-2.5.2/webapp2.py", line 570, in dispatch
    return method(*args, **kwargs)
  File "/Users/mgilson/git/spider-web/app/pattern/handlers/ajax/email.py", line 77, in post
    'success': int(client.send_draft(draft_id))
  File "/Users/mgilson/git/spider-web/app/pattern/services/email/gmail.py", line 603, in send_draft
    .execute(http=self._http)
  File "/Users/mgilson/git/spider-web/app/third_party/oauth2client/util.py", line 140, in positional_wrapper
    return wrapped(*args, **kwargs)
  File "/Users/mgilson/git/spider-web/app/third_party/googleapiclient/http.py", line 729, in execute
    raise HttpError(resp, content, uri=self.uri)
HttpError: <HttpError 400 when requesting https://www.googleapis.com/gmail/v1/users/me/drafts/send?alt=json returned "Invalid draft">

这让我觉得可能朝着正确的方向前进......（注意，我已经能够使用ID从上面链接的API资源管理器发送消息，所以我确信我正在使用有效的身份证明

发送此数据的正确方法是什么？

我不确定这是多么相关，但可以在https://www.googleapis.com/discovery/v1/apis/gmail/v1/rest

找到发现API的GMAIL Api表示。

具体来说，我认为我使用的方法是由以下JSON定义的：

  "send": {
   "id": "gmail.users.drafts.send",
   "path": "{userId}/drafts/send",
   "httpMethod": "POST",
   "description": "Sends the specified, existing draft to the recipients in the To, Cc, and Bcc headers.",
   "parameters": {
    "userId": {
     "type": "string",
     "description": "The user's email address. The special value me can be used to indicate the authenticated user.",
     "default": "me",
     "required": true,
     "location": "path"
    }
   },
   "parameterOrder": [
    "userId"
   ],
   "request": {
    "$ref": "Draft"
   },
   "response": {
    "$ref": "Message"
   },
   "scopes": [
    "https://mail.google.com/",
    "https://www.googleapis.com/auth/gmail.compose",
    "https://www.googleapis.com/auth/gmail.modify"
   ],
   "supportsMediaUpload": true,
   "mediaUpload": {
    "accept": [
     "message/rfc822"
    ],
    "maxSize": "35MB",
    "protocols": {
     "simple": {
      "multipart": true,
      "path": "/upload/gmail/v1/users/{userId}/drafts/send"
     },
     "resumable": {
      "multipart": true,
      "path": "/resumable/upload/gmail/v1/users/{userId}/drafts/send"
     }
    }
   }
  },

Answer 1

查看Gmail API Python docs，看起来第二个参数是请求的body。根据{{3}}，您需要在正文中使用id字段，并且要发送草稿的draftId：

service.users().drafts().send(
    userId='me', body={ 'id': draft_id }).execute(http=http)

使用googleapiclient通过Id发送电子邮件草稿

1 个答案: