我知道我之前曾在某个地方见到过一些例子,但对于我的生活,我在谷歌搜索时找不到它。
我有一些数据行:
data = [[1,2,3],
[4,5,6],
[7,8,9],
]
我想在表格中输出这些数据,例如
+---+---+---+
| 1 | 2 | 3 |
+---+---+---+
| 4 | 5 | 6 |
+---+---+---+
| 7 | 8 | 9 |
+---+---+---+
显然我可以使用类似漂亮的图书馆或下载熊猫或其他东西,但我对此非常不感兴趣。
我只想在Jupyter笔记本单元格中输出行作为表格。我该怎么做?
答案 0 :(得分:53)
我刚刚发现tabulate有一个HTML选项,使用起来相当简单 与Wayne Werner的答案非常相似:
from IPython.display import HTML, display
import tabulate
table = [["Sun",696000,1989100000],
["Earth",6371,5973.6],
["Moon",1737,73.5],
["Mars",3390,641.85]]
display(HTML(tabulate.tabulate(table, tablefmt='html')))
还在寻找一些简单易用的东西来创建更复杂的表格布局,比如使用乳胶语法和格式来合并单元格并在笔记本中进行变量替换:
Allow references to Python variables in Markdown cells #2958
答案 1 :(得分:42)
我终于重新找到了我正在寻找的jupyter/IPython documentation。
我需要这个:
display(HTML('some html here'))
(我可能略微理解了这些理解,但我们需要if((j+k) > 26)
)
答案 2 :(得分:32)
有一个很好的技巧:用pandas DataFrame包装数据。
import pandas as pd
data = [[1, 2], [3, 4]]
pd.DataFrame(data, columns=["Foo", "Bar"])
显示如下数据:
| Foo | Bar |
0 | 1 | 2 |
1 | 3 | 4 |
答案 3 :(得分:6)
tabletext很适合
import tabletext
data = [[1,2,30],
[4,23125,6],
[7,8,999],
]
print tabletext.to_text(data)
结果:
┌───┬───────┬─────┐
│ 1 │ 2 │ 30 │
├───┼───────┼─────┤
│ 4 │ 23125 │ 6 │
├───┼───────┼─────┤
│ 7 │ 8 │ 999 │
└───┴───────┴─────┘
答案 4 :(得分:4)
如果您不介意使用一些html,则应该可以使用这种方法。
from IPython.display import HTML, display
def display_table(data):
html = "<table>"
for row in data:
html += "<tr>"
for field in row:
html += "<td><h4>%s</h4><td>"%(field)
html += "</tr>"
html += "</table>"
display(HTML(html))
然后像这样使用它
data = [[1,2,3],[4,5,6],[7,8,9]]
display_table(data)
答案 5 :(得分:2)
您可以尝试使用以下功能
def tableIt(data):
for lin in data:
print("+---"*len(lin)+"+")
for inlin in lin:
print("|",str(inlin),"", end="")
print("|")
print("+---"*len(lin)+"+")
data = [[1,2,3,2,3],[1,2,3,2,3],[1,2,3,2,3],[1,2,3,2,3]]
tableIt(data)
答案 6 :(得分:2)
好的,所以这比我更难:
def print_matrix(list_of_list):
number_width = len(str(max([max(i) for i in list_of_list])))
cols = max(map(len, list_of_list))
output = '+'+('-'*(number_width+2)+'+')*cols + '\n'
for row in list_of_list:
for column in row:
output += '|' + ' {:^{width}d} '.format(column, width = number_width)
output+='|\n+'+('-'*(number_width+2)+'+')*cols + '\n'
return output
这适用于可变数量的行,列和位数(对于数字)
data = [[1,2,30],
[4,23125,6],
[7,8,999],
]
print print_matrix(data)
>>>>+-------+-------+-------+
| 1 | 2 | 30 |
+-------+-------+-------+
| 4 | 23125 | 6 |
+-------+-------+-------+
| 7 | 8 | 999 |
+-------+-------+-------+
答案 7 :(得分:2)
一组通用的函数集,用于将任何python数据结构(dicts和列表嵌套在一起)呈现为HTML。
from IPython.display import HTML, display
def _render_list_html(l):
o = []
for e in l:
o.append('<li>%s</li>' % _render_as_html(e))
return '<ol>%s</ol>' % ''.join(o)
def _render_dict_html(d):
o = []
for k, v in d.items():
o.append('<tr><td>%s</td><td>%s</td></tr>' % (str(k), _render_as_html(v)))
return '<table>%s</table>' % ''.join(o)
def _render_as_html(e):
o = []
if isinstance(e, list):
o.append(_render_list_html(e))
elif isinstance(e, dict):
o.append(_render_dict_html(e))
else:
o.append(str(e))
return '<html><body>%s</body></html>' % ''.join(o)
def render_as_html(e):
display(HTML(_render_as_html(e)))
答案 8 :(得分:1)
我曾经遇到过同样的问题。我找不到任何可以帮助我的东西,所以我最终创建了课程PrintTable
- 代码如下。还有一个输出。用法很简单:
ptobj = PrintTable(yourdata, column_captions, column_widths, text_aligns)
ptobj.print()
或一行:
PrintTable(yourdata, column_captions, column_widths, text_aligns).print()
输出:
-------------------------------------------------------------------------------------------------------------
Name | Column 1 | Column 2 | Column 3 | Column 4 | Column 5
-------------------------------------------------------------------------------------------------------------
Very long name 0 | 0 | 0 | 0 | 0 | 0
Very long name 1 | 1 | 2 | 3 | 4 | 5
Very long name 2 | 2 | 4 | 6 | 8 | 10
Very long name 3 | 3 | 6 | 9 | 12 | 15
Very long name 4 | 4 | 8 | 12 | 16 | 20
Very long name 5 | 5 | 10 | 15 | 20 | 25
Very long name 6 | 6 | 12 | 18 | 24 | 30
Very long name 7 | 7 | 14 | 21 | 28 | 35
Very long name 8 | 8 | 16 | 24 | 32 | 40
Very long name 9 | 9 | 18 | 27 | 36 | 45
Very long name 10 | 10 | 20 | 30 | 40 | 50
Very long name 11 | 11 | 22 | 33 | 44 | 55
Very long name 12 | 12 | 24 | 36 | 48 | 60
Very long name 13 | 13 | 26 | 39 | 52 | 65
Very long name 14 | 14 | 28 | 42 | 56 | 70
Very long name 15 | 15 | 30 | 45 | 60 | 75
Very long name 16 | 16 | 32 | 48 | 64 | 80
Very long name 17 | 17 | 34 | 51 | 68 | 85
Very long name 18 | 18 | 36 | 54 | 72 | 90
Very long name 19 | 19 | 38 | 57 | 76 | 95
-------------------------------------------------------------------------------------------------------------
班级PrintTable
# -*- coding: utf-8 -*-
# Class
class PrintTable:
def __init__(self, values, captions, widths, aligns):
if not all([len(values[0]) == len(x) for x in [captions, widths, aligns]]):
raise Exception()
self._tablewidth = sum(widths) + 3*(len(captions)-1) + 4
self._values = values
self._captions = captions
self._widths = widths
self._aligns = aligns
def print(self):
self._printTable()
def _printTable(self):
formattext_head = ""
formattext_cell = ""
for i,v in enumerate(self._widths):
formattext_head += "{" + str(i) + ":<" + str(v) + "} | "
formattext_cell += "{" + str(i) + ":" + self._aligns[i] + str(v) + "} | "
formattext_head = formattext_head[:-3]
formattext_head = " " + formattext_head.strip() + " "
formattext_cell = formattext_cell[:-3]
formattext_cell = " " + formattext_cell.strip() + " "
print("-"*self._tablewidth)
print(formattext_head.format(*self._captions))
print("-"*self._tablewidth)
for w in self._values:
print(formattext_cell.format(*w))
print("-"*self._tablewidth)
示范
# Demonstration
headername = ["Column {}".format(x) for x in range(6)]
headername[0] = "Name"
data = [["Very long name {}".format(x), x, x*2, x*3, x*4, x*5] for x in range(20)]
PrintTable(data, \
headername, \
[70, 10, 10, 10, 10, 10], \
["<",">",">",">",">",">"]).print()
答案 9 :(得分:0)
我想输出一个表,其中每列的宽度尽可能小,
其中列用空格填充(但可以更改),行由换行符分隔(但可以更改),并使用str
(但......)格式化每个项目。
def ftable(tbl, pad=' ', sep='\n', normalize=str):
# normalize the content to the most useful data type
strtbl = [[normalize(it) for it in row] for row in tbl]
# next, for each column we compute the maximum width needed
w = [0 for _ in tbl[0]]
for row in strtbl:
for ncol, it in enumerate(row):
w[ncol] = max(w[ncol], len(it))
# a string is built iterating on the rows and the items of `strtbl`:
# items are prepended white space to an uniform column width
# formatted items are `join`ed using `pad` (by default " ")
# eventually we join the rows using newlines and return
return sep.join(pad.join(' '*(wid-len(it))+it for wid, it in zip(w, row))
for row in strtbl)
函数签名ftable(tbl, pad=' ', sep='\n', normalize=str)
及其默认参数用于
提供最大的灵活性。
您可以自定义
pad='&', sep='\\\\\n'
拥有大量LaTeX表)str
但是如果
你知道你的所有数据都是浮点lambda item:
"%.4f"%item
可能是一个合理的选择,等等。表面测试:
我需要一些测试数据,可能涉及不同宽度的列 所以算法需要更复杂一些(但只是一点点);
In [1]: from random import randrange
In [2]: table = [[randrange(10**randrange(10)) for i in range(5)] for j in range(3)]
In [3]: table
Out[3]:
[[974413992, 510, 0, 3114, 1],
[863242961, 0, 94924, 782, 34],
[1060993, 62, 26076, 75832, 833174]]
In [4]: print(ftable(table))
974413992 510 0 3114 1
863242961 0 94924 782 34
1060993 62 26076 75832 833174
In [5]: print(ftable(table, pad='|'))
974413992|510| 0| 3114| 1
863242961| 0|94924| 782| 34
1060993| 62|26076|75832|833174
答案 10 :(得分:0)
我最近使用prettytable
来渲染漂亮的ASCII表。它类似于postgres CLI输出。
import pandas as pd
from prettytable import PrettyTable
data = [[1,2,3],[4,5,6],[7,8,9]]
df = pd.DataFrame(data, columns=['one', 'two', 'three'])
def generate_ascii_table(df):
x = PrettyTable()
x.field_names = df.columns.tolist()
for row in df.values:
x.add_row(row)
print(x)
return x
generate_ascii_table(df)
输出:
+-----+-----+-------+
| one | two | three |
+-----+-----+-------+
| 1 | 2 | 3 |
| 4 | 5 | 6 |
| 7 | 8 | 9 |
+-----+-----+-------+