Question

var array = [
    { T: 2, G: 2, K: 2},        //<--- return this cause T+G+K = 6
    { T: 2, G: 2, K: 3},
    { T: 1, G: 3, K: 2}         //<--- return this cause T+G+K = 6
];

我想从数组返回相同数量的字段对象。怎么做？

我当时想：

var array = [
    { T: 2, G: 2, K: 2 },        //<--- return this cause T+G+K = 6
    { T: 2, G: 2, K: 3 },
    { T: 1, G: 3, K: 2 }         //<--- return this cause T+G+K = 6
];  

//getting uniq array
var uniqArray = _.uniq(array, function(value) {
    return value.T + value.G + value.K;
}

//uniqArray = [
//  { T: 2, G: 2, K: 2 },
//  { T: 2, G: 2, K: 3 }
//];

//getting the difference between uniq and normal array
var differenceArray = _.difference(array, uniqArray);

//differenceArray = [
//  { T: 1, G: 3, K: 2 }
//];

//and finally try to get the same objects in array like:
var theSame = [];
_.each(array, function(value) {
    if((value.T + value.G + value.K) === _.each(differenceArray, function(num) {
    return num.T + num.G + num.K; }) {
        theSame.push(value);
    }
);

但我真的不知道下划线，所以我认为我试图通过过多使用并使其变得太难来做某事。我怎样才能轻松获得这些物品？

谢谢

Answer 1

如果我理解你，这应该最终有用。

var array = [
  { T: 2, G: 2, K: 2 },
  { T: 2, G: 2, K: 3 },
  { T: 1, G: 3, K: 2 }
];

var uniqArray = _.uniq(array, function(value) {
  return value.T + value.G + value.K;
});

var differenceArray = _.difference(array, uniqArray);

var sums = _.map(differenceArray, function(item) {
  return item.T + item.G + item.K;
});

var result = _.filter(array, function(item) {
  var sum = item.T + item.G + item.K; 
  return _.contains(sums, sum);
});

更干净的版本：

var arraySum = function(item) {
  return item.T + item.G + item.K;
};

var notUniqueSums = _.chain(array)
  .difference(_.uniq(array, arraySum))
  .map(arraySum)
  .value();

var result = _.filter(array, function(item) { 
  return _.contains(notUniqueSums, arraySum(item));
});

下划线 - 从数组中获取值对象的相同值

1 个答案: