嘿,我有以下 badwords ,我想查看它们是否在我传递的字符串中:
Private Function injectionCheck(queryString As String) As Integer
Dim badWords() As String = {"EXEC", "EXECUTE", ";", "-", "*", "--", "@",
"UNION", "DROP", "DELETE", "UPDATE", "INSERT", "MASTER",
"TABLE", "XP_CMDSHELL", "CREATE", "XP_FIXEDDRIVES",
"SYSCOLUMNS", "SYSOBJECTS"}
Dim pattern As String = "\b(" + Regex.Escape(badWords(0))
For Each key In badWords.Skip(1)
pattern += "|" + Regex.Escape(key)
Next
pattern += ")\b"
Return Regex.Matches(queryString, pattern, RegexOptions.IgnoreCase).Count
End Function
对于模式,我得到以下内容:
\b(EXEC|EXECUTE|;|-|\*|--|@|UNION|DROP|DELETE|UPDATE|INSERT|MASTER|TABLE|XP_CMDSHELL|
CREATE|XP_FIXEDDRIVES|SYSCOLUMNS|SYSOBJECTS)\b
哪个看起来对我不对。但每当我打电话给它时,我会得到 0 作为对此的回应:
Dim blah As Integer = injectionCheck("select * from bob where something = 'you'")
所以我要忽略的是因为上面不应该返回 0 - 它应该返回 2 因为*和'使用不应该使用。
答案 0 :(得分:2)
如果您计划将单词作为整个单词进行匹配,但关键字可能以非单词字符开头/结尾,则可能会遇到类似的问题。单词边界含义取决于上下文:\b--\b
将匹配X--X
但不会匹配, --,
。
您需要明确的边界匹配。使用lookarounds (?<!\w)
作为前导,(?!\w)
作为尾随单词边界。
实施如下所示的更改:
Dim pattern As String = "(?<!\w)(" + Regex.Escape(badWords(0)) ' <== HERE
For Each key In badWords.Skip(1)
pattern += "|" + Regex.Escape(key)
Next
pattern += ")(?!\w)" ' <== AND HERE