Question

我有这样的变量#aa0000 如何删除AA55BBB(888)1234567890P1和)之间的字符？

Answer 1

通常你用正则表达式来做，但AS2不支持它们。所以另一个（老式的）解决方案是将这些字符上的字符串拆分并再次加入

这假设您只有一个＆＃34;）＆＃34;和一个＆＃34; P＆＃34;在你的字符串中：

var myString:String = "AA55BBB(888)1234567890P1";

// this will result in an Array like ["AA55BBB(888", "1234567890P1"];
var firstSplit:Array = myString.split(")");

var firstPart:String = firstSplit[0]; // "AA55BBB(888"
var secondPart:String = firstSplit[1]; // "1234567890P1"

var secondSplit:Array = secondPart.split("P"); // ["1234567890","1"]

secondPart = secondSplit[1]; //"1"

// since we have removed the ")" and "P" on split, put them back in
var newString:String = firstPart + ")P" + secondPart;

trace(newString); // "AA55BBB(888)P1"

AS2 - 如何在specyfic字符后删除字符

1 个答案: