Question

这是我的数组的输出

我希望每次在数组中更改索引时搜索哪个值都在哪个索引上这是第二次屏幕截图

我如何检查例如我想搜索值男性被放置在哪个索引上并且还要检查放置的值是否存在平均值是否存在

public function ajax(){
    $array      = $_POST['checkbox'];

    $searchTerm = "male";

if (false !== ($pos = $this->array_search2d_by_field($searchTerm, $array))) {
echo $searchTerm . " found at index " . $pos;
} else {
echo "Could not find " . $searchTerm;
}


}
function array_search2d_by_field($needle, $haystack) {
foreach ($haystack as $index => $innerArray) {
    if (isset($innerArray) && $innerArray === $needle) {
        return $index;
    }
}
return false;
}

Answer 1

您可以使用array_search功能：

示例＃1 array_search（）示例

<?php
$array = array(0 => 'blue', 1 => 'red', 2 => 'green', 3 => 'red');
$key = array_search('green', $array); // $key = 2;
$key = array_search('red', $array);   // $key = 1;
?>

in_array功能：

示例＃1 in_array（）示例

<?php
$os = array("Mac", "NT", "Irix", "Linux");
if (in_array("Irix", $os)) {
    echo "Got Irix";
}
if (in_array("mac", $os)) {
    echo "Got mac";
}
?>

Answer 2

试试这段代码。

这是一种基于您选中的复选框值的灵活搜索

function filterartion($array){

    $array = array(
        '0' => 'av', 
        '1' => 'nav', 
        '2' => 'male', 
        '3' => 'female', 
        '4' => 'A+', 
        '5' => 'A-', 
    );

    // Gender
    if(in_array("male", $array))
    {
        $gender[] =  'male';
    }
    if(in_array("female", $array))
    {
        $gender[] = 'female';
    }

    // Status
    if(in_array("av", $array))
    {
        $status[] =  '1';
    }
    if(in_array("nav", $array))
    {
        $status[] = '0';
    }

    // Group
    if(in_array("A+", $array))
    {
        $group[] =  'A+';
    }
    if(in_array("A-", $array))
    {
        $group[] = 'A-';
    }

    $this->db->slect("*");
    $this->db->from("members");
    $this->db->where_in('gender', $gender);
    $this->db->where_in('status', $status);
    $this->db->where_in('blood_group', $group);
    $query = $this->db->get();
    $result = $query->result_array();
    // return $result;
    print_r($result);
}

Answer 3

public function ajax(){
    $array      = $_POST['checkbox'];

    $searchTerm = "male";

if (false !== ($pos = $this->array_search2d_by_field($searchTerm, $array))) {
echo $searchTerm . " found at index " . $pos;
} else {
echo "Could not find " . $searchTerm;
}


}
function array_search2d_by_field($needle, $haystack) {
foreach ($haystack as $index => $innerArray) {
    if (isset($innerArray) && $innerArray === $needle) {
        return $index;
    }
}
return false;

}

[![enter image description here][1]][1]

在codeigniter中根据欲望项获取数组索引的值

3 个答案: