拥有Vector＆＃34; data1 ＆＃34;有这样的价值......
DefaultTableModel model1 = (DefaultTableModel)itemsTableSD.getModel();
Vector data1 = model1.getDataVector();
System.out.println(data1.toString());
结果1：
[[row-0-col-0, row-0-col-1, row-0-col-2, row-0-col-3, row-0-col-4, row-0-col-5], [row-1-col-0, row-1-col-1, row-1-col-2, row-1-col-3, row-1-col-4, row-1-col-5]]
如果循环通过Vector
for(int i=0; i<dataMG.size(); i++){
System.out.println("data1: "+ "Row-" + i + "->" +dataMG.get(i));
System.out.println("\n");
}
我只获得行......
data1: Row-0->[row-0-col-0, row-0-col-1, row-0-col-2, row-0-col-3, row-0-col-4, row-0-col-5]
data1: Row-1->[row-1-col-0, row-1-col-1, row-1-col-2, row-1-col-3, row-1-col-4, row-1-col-5]
问题：
如何从每一行获取单个项目......
像...
row-0-col-0
row-0-col-1
row-0-col-2
...
row-1-col-3
row-1-col-4
row-1-col-5
请指点我，谢谢