Question

我试图制作一个抽搐的程序，例如，通过输入命令（＆＃34;！voteA＆＃34;），抽搐聊天可以投票，而聊天机器人代码将计算投票，并且在GUI窗口中显示它们，我已经相当远了，但是我的GUI窗口没有打开，我认为它与self.after（10，self.get_votes）行有关，任何人都可以帮忙我出去了吗？

这里是代码:(它有更多标签，如阅读，套接字，初始化，设置，但我不认为他们现在相关，如果他们是我也可以发布它们）

import Tkinter as tk
from Read import getUser, getMessage
from Socket import openSocket, sendMessage
from Initialize import joinRoom
from collections import OrderedDict

class App(tk.Frame): #Toplevel is a frame with a specific use. Unless there is another window, you want a Frame.
    def __init__(self):
        options = [
            "voteA",
            "voteB",
            "voteC"]

        self.s = openSocket()
        joinRoom(self.s)
        self.readbuffer = ""

        tk.Frame.__init__(self)
        self['background']='black'
        self.pack()
        self.master.geometry("+200+200")
        # self.master.attributes("-alpha", 0.7)

        self.labels = OrderedDict()
        for option in options:
            label = tk.Label(
                self,
                bg="black",
                fg="white",
                font="HouseSlant-Regular 30",
                anchor="w")
            label.pack()
            self.labels[option] = [0, label]

        self.update_text()
        self.after(10, self.get_votes)

    def update_text(self):
        for name, data in self.labels.items():
            count, label = data
            label['text'] = "{} has {} votes".format(name, count)

    def get_votes(self):
        self.after(10, self.get_votes)

        self.readbuffer = self.readbuffer + self.s.recv(1024)
        temp = self.readbuffer.split('\n')
        self.readbuffer = temp.pop() #save the last (possibly incomplete) line for later
        if self.readbuffer == "":
            pass #no further messages in the queue
            #you should add a sleep time here for the sake of your hot NIC

        for line in temp:
            print(line)

            if "PING" in line:
                s.send("PONG :tmi.twitch.tv\r\n".encode())
                break

            user = getUser(line)
            message = getMessage(line)

            print "{} typed: {}".format(user, message)

            if "!commands" in message:
                sendMessage(self.s, " ".join(["!"+option for option in self.labels]))
                break

            for option in self.labels:
                if "!"+option in message:
                    self.labels[option][0] += 1
                    print self.labels[option][0]
                    self.update_text() 

app=App()
app.mainloop()

运行代码时会发生什么，聊天机器人的工作原理是什么;如果我输入＆＃34;！命令＆＃34;或＆＃34;！voteA＆＃34;它会很好地响应，但GUI窗口不会打开。我可以在我的Dock（我是一个mac用户）中看到它试图打开一个窗口，但它冻结然后我必须强行退出它。它虽然没有在编译器中给出错误。有没有人知道我搞砸了什么？

Tkinter＆＃39; .after（）＆＃39;帮助，GUI窗口不打开

0 个答案: