Question

我有这个XML

<CurrencyExchangeMap>
<CurrencyExchangePoint>
    <Address>addr 3</Address>
    <Latitude>41.6940265</Latitude>
    <Longitude>44.7985044</Longitude>
</CurrencyExchangePoint>
<CurrencyExchangePoint>
    <Address>addr 4</Address>
    <Latitude>41.7024424</Latitude>
    <Longitude>44.8058617</Longitude>
</CurrencyExchangePoint>
<CurrencyExchangePoint>
    <Address>addr 5</Address>
    <Latitude>41.6954418</Latitude>
    <Longitude>44.7046725</Longitude>
</CurrencyExchangePoint>
</CurrencyExchangeMap>

我正在使用以下方法解析它：

列出mapLTList;

private MapLT mapLT;
private String text;

public XMLPullParserHandler() {
    mapLTList = new ArrayList<MapLT>();
}

public List<MapLT> getMapLT(){
    return mapLTList;
}

public List<MapLT> parse(InputStream is){
    XmlPullParserFactory factory = null;
    XmlPullParser parser = null;

    try{
        factory = XmlPullParserFactory.newInstance();
        factory.setNamespaceAware(true);

        parser = factory.newPullParser();
        parser.setInput(is, null);

        int eventType = parser.getEventType();
        while(eventType != XmlPullParser.END_DOCUMENT){
            String tagname = parser.getName();
            switch (eventType){
                case XmlPullParser.START_TAG:
                    if(tagname.equalsIgnoreCase("CurrencyExchangeMap")){
                        mapLT = new MapLT();
                    }
                    break;
                case XmlPullParser.TEXT:
                    text = parser.getText();
                    break;
                case XmlPullParser.END_TAG:
                    if(tagname.equalsIgnoreCase("CurrencyExchangePoint")){
                        mapLTList.add(mapLT);
                    } else if(tagname.equalsIgnoreCase("Address")){
                        mapLT.setAddress(text);
                    } else if(tagname.equalsIgnoreCase("Latitude")){
                        mapLT.setLatitude(Float.parseFloat(text));
                    } else if(tagname.equalsIgnoreCase("Longitude")){
                        mapLT.setLongitude(Float.parseFloat(text));
                    }
                    break;
                default:
                    break;
            }
            eventType = parser.next();
        }

    }catch (Exception ex){
        ex.printStackTrace();
    }
    return  mapLTList;
}

但结果中有3个地址，每个地址都是Addr 5（最后一个元素）。怎么了？

Answer 1

您的MapLit包含有关CurrencyExchangePoint（xml中的三个项目）的信息，但您将其视为CurrencyExchangeMap（xml中的一项）。这样，您可以反复重复使用相同的引用，覆盖其内容。变化

  case XmlPullParser.START_TAG:
      if(tagname.equalsIgnoreCase("CurrencyExchangeMap")){
             mapLT = new MapLT();
      }

与

case XmlPullParser.START_TAG:
  if(tagname.equalsIgnoreCase("CurrencyExchangePoint")){
         mapLT = new MapLT();
  }

解析xml只返回最后一行

1 个答案: