Question

我花了好几个小时试图找出问题，但没有运气：/ 我正在运行此查询：

if($_POST) {
    $ask_name = mysqli_real_escape_string($connect, $_POST['ask_name']);
    $ask_email = mysqli_real_escape_string($connect, $_POST['ask_email']);
    $ask_text = mysqli_real_escape_string($connect, $_POST['ask_text']);
    $ask_category = mysqli_real_escape_string($connect, $_GET['categ']);
    $ask_time = date("d-F-Y");

    if($ask_name = "" || $ask_email == "" || $ask_text == "" || $ask_category == "") {
        $msg = '<span class="fa fa-exclamation-triangle fa-lg"></span> Fill Out All Inputs Please';
    }

    else {  
        $insert_post = mysqli_query($connect, "INSERT INTO forum_posts (name, email, text, category, time) VALUES ('$ask_name', '$ask_email', '$ask_text', '$ask_category', '$ask_time')");
        header('Location: forum.php?categ=' .$ask_category);
        exit(); 
    }
}

这是我的php文件中的表单

<!--Insert Post-->
   <form id="ask-question" method="post" name="ask_question" action="">
    <label for="ask-name">Your Name</label><br>
    <input type="text" name="ask_name" id="ask-name"><br>
    <label for="ask-email">Your E-Mail (Won't be displayed)</label><br>
    <input type="email" name="ask_email" id="ask-email"><br>
    <label for="ask-text">Your Question</label><br>
    <textarea name="ask_text" id="ask-text"></textarea><br>
    <input type="submit" name="post_submit" value="Ask Now" id="post-submit">
    <?php if(isset($msg)) { echo('<p>' .$msg. '</p>'); } ?>
   </form>

问题是查询没有插入＆＃34;名称＆＃34;值。所有其他值都成功插入到我的mysql数据库中，但是＆＃34; name＆＃34;价值。

有什么想法吗？非常感谢你！

Answer 1

您在=条件中使用了单if符号而非双倍。

更改

if($ask_name = ""...

到

if($ask_name == ""...
              ^

否则您将空字符串分配给该变量

Answer 2

$ask_name = ""表示您正在为该变量分配空值。

更改

if($ask_name = "" || $ask_email == "" || $ask_text == "" || $ask_category == "")

到

if($ask_name == "" || $ask_email == "" || $ask_text == "" || $ask_category == "")

Mysqli查询不会插入第一个值

2 个答案: