Question

我正在使用带有Hibernate的Spring JPA Repository进入MySQL数据库。在那个环境中，我有以下实体：

@Entity
@Table(name="cod__postales")
public class CodigoPostal {

    @Id
    @GeneratedValue
    private Long registro;

    @Column(name = "`POST_Nº_CODIGO`", length = 6, nullable = false)
    private String codigo = "  ";

    @Column(name = "POST_DESCRIP", length = 30, nullable = false)
    private String descripcion = "                              ";

    @Column(name = "POST_ZONA_ASIG", length = 2, nullable = false)
    private String zona = "  ";

此外，我还有以下Spring JPA存储库：

public interface CodigoPostalRepository extends JpaRepository<CodigoPostal, Long> {

    CodigoPostal findOneByCodigo(String codigo);

}

如您所见，第一列名称'º'上有一个特殊字符。问题在于，当我调用 repo.findOneByCodigo（）方法时，会生成以下SQL

select codigopost0_.registro as registro1_2_,
    codigopost0_.`post_nº_codigo` as post_nº_2_2_,
    codigopost0_.post_descrip as post_des3_2_,
    codigopost0_.post_zona_asig as post_zon4_2_
from cod__postales codigopost0_
where codigopost0_.`post_nº_codigo`=?

问题是sql因为名称spring / hibernate对该列的分配而产生错误： aspost_nº_2_2_。

我该如何避免这种情况？

Answer 1

这是关于此查询的第一个想法，我的建议是引入一个原生查询，它可以帮助您将'更改为post_nº_2_2_。'更改为：' as post_n_2_2 _。< /强>”。

示例：

@Query(value = " select codigopost0_.registro as registro1_2_, codigopost0_.`post_nº_codigo` as post_n_2_2_, codigopost0_.post_descrip as post_des3_2_, codigopost0_.post_zona_asig as post_zon4_2_ from cod__postales codigopost0_ where codigopost0_.`post_nº_codigo`=?", nativeQuery = true) public interface CodigoPostalRepository extends JpaRepository<CodigoPostal, Long> { CodigoPostal findOneByCodigo(String codigo); }

有关此link的更多信息。

Answer 2

最后我通过将characterEncoding参数添加到url字符串来解决这个问题：

spring.datasource.url=jdbc:mysql://localhost/madr?characterEncoding=UTF-8

无论如何，我已经向Hibernate打开了一个问题，因为对于每个人来说这可能不是一个有效的选项https://hibernate.atlassian.net/browse/HHH-10493

Answer 3

更改

@Column(name = "`POST_Nº_CODIGO`", length = 6, nullable = false)

到

@Column(name = "`POST_N_CODIGO`", length = 6, nullable = false)

Spring JPA Repository生成错误的SQL

3 个答案: