Question

我在医疗数据库中有3个表，

表：成员

    id_member    name
    1            Pendi
    2            Ardi
    3            Hafiz
    4            Arista

表：好处

    id_member              id_benefit     year
    1                      1              2016
    1                      2              2016
    1                      3              2016
    2                      4              2016
    2                      5              2016
    2                      6              2016
    3                      7              2016
    3                      8              2016
    3                      9              2016
    4                      10             2016
    4                      11             2016
    4                      12             2016

表：masterbenefit

 id_masterbenefit       benefit_name        benefit_value
    1                      inpatient           100000
    2                      outpatient          2000
    3                      dental              300
    4                      inpatient           150000
    5                      outpatient          2500
    6                      dental              350
    7                      inpatient           170000
    8                      outpatient          2750
    9                      dental              375
    10                     inpatient           190000
    11                     outpatient          2900
    12                     dental              390

我想在一个表格中显示

No.  Member-Name     Year       Inpatient        Outpatient     Dental
1.   Pendi           2016       100000           2000           300
2.   Ardi            2016       150000           2500           350
3.   Hafiz           2016       170000           2750           375
4.   Arista          2016       190000           2900           390

我有这样的查询（来自本网站的其他问题），但这不是我需要的。

SELECT A.name NAME,
CASE WHEN B.id_benefit='1' THEN C.benefit_value END Inpatient,
CASE WHEN B.id_benefit='2' THEN C.benefit_value END Outpatient,
CASE WHEN B.id_benefit='3' THEN C.benefit_value END Dental,
CASE WHEN B.id_benefit='4' THEN C.benefit_value END Inpatient,
CASE WHEN B.id_benefit='5' THEN C.benefit_value END Outpatient,
CASE WHEN B.id_benefit='6' THEN C.benefit_value END Dental,
CASE WHEN B.id_benefit='7' THEN C.benefit_value END Inpatient,
CASE WHEN B.id_benefit='8' THEN C.benefit_value END Outpatient,
CASE WHEN B.id_benefit='9' THEN C.benefit_value END Dental,
CASE WHEN B.id_benefit='10' THEN C.benefit_value END Inpatient,
CASE WHEN B.id_benefit='11' THEN C.benefit_value END Outpatient,
CASE WHEN B.id_benefit='12' THEN C.benefit_value END Dental,
FROM member A, benefit B, masterbenefit C
WHERE A.id_member=B.id_member
AND B.id_benefit=C.id_masterbenefit
GROUP BY A.id_member
ORDER BY A.name

Answer 1

使用Joins组合数据和group by为每个成员分组数据：

试试这个：

select 
  @row_num:=@row_num+1 as no,
  m.name,
  b.year,
  max(if(mb.benefit_name='inpatient',mb.benefit_value,0)) as inpatient,
  max(if(mb.benefit_name='outpatient',mb.benefit_value,0)) as outpatient,
  max(if(mb.benefit_name='dental',mb.benefit_value,0)) as dental
from member m
inner join benefit b on m.id_member=b.id_member
inner join masterbenefit mb on b.id_benefit=mb.id_masterbenefit,(select @row_num:=0) as p
group by m.id_member,b.year

SQL小提琴：http://sqlfiddle.com/#!9/7e1250/3

将记录转换为mysql中3个表的记录

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