Question

我无法将此代码转换为codeigniter。请帮忙

SELECT * FROM table1
LEFT JOIN table2 ON table2.number = table1.number
WHERE table2.number IS NULL

Answer 1

使用以下代码。

$this->db->select('*');
$this->db->from('table1');
$this->db->join('table2 ', 'table2.number = table1.number','left');
$this->db->where('table2.number IS NULL'); 
$query = $this->db->get();

Answer 2

试试这个

 if($this->db->query('SELECT * FROM table1 LEFT JOIN table2 ON table2.number = table1.number WHERE table2.number IS NULL') )
  {  
     echo 'success';
  }
   else
       echo 'check your query';

示例：

var async = require('async');

var prodAdvOptions = {
    host : "webservices.amazon.in",
    region : "IN",
    version : "2013-08-01",
    path : "/onca/xml"
};
var prodAdv = aws.createProdAdvClient(awsAccessKeyId, awsSecretKey, awsAssociateTag, prodAdvOptions);

var n=100;//Just for test
var i = 0;  // part 1 of for loop (var i = 0)
async.whilst(
    function () { return i <= n; },  // part 2 of for loop (i <=n)
    function (callback) {
        prodAdv.call("ItemSearch", {
            SearchIndex : "All",
            Keywords : "health,fitness,baby care,beauty",
            ResponseGroup : 'Images,ItemAttributes,Offers,Reviews',
            Availability : 'Available',
            ItemPage : 1
        }, function(err, result) {
            if (err) {
                console.log(err);
            } else {
                console.log(result);
            }
            i++;          // part 3 of for loop (i++)
            callback();
        });
    },
    function (err) {
        console.log('done with all items from 0 - 100');
    }
);

Answer 3

$this->db->where('table2.number IS NOT NULL', null, false)

OR

$this->db->where(array('table2.number' IS NOT NULL));

Answer 4

你可以这样做。

$this->db->select('*');
$this->db->from('table1');
$this->db->join('table2 ', 'table2 .user_id = table1.id','left');
$this->db->where('table1.users_id', $id); 
$query = $this->db->get();

Answer 5

使用它：

$this->db->select('*')
         ->from('table1')
         ->join('table2 ', 'table2.number = table1.number','left')
         ->where('table2.users_id', NULL ); 
$query = $this->db->get();

Codeigniter：转换代码

5 个答案: