问题:如何以编程方式突出显示ListView中的选项?
背景:我已经看过很多关于这类问题的线索,但似乎都没有。我在一个片段中有一个列表视图,该片段由使用自定义适配器从数据库创建的列表填充。当片段打开时,我希望默认选择其中一个项目(取决于编辑模式是否为1 /启用),我已准备好此项目的位置。我目前使用的是clientList.setChoiceMode(ListView.CHOICE_MODE_SINGLE)
,并尝试使用setItemChecked
突出显示该选项,但它不起作用。
Fragment OnCreate
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
FragmentActivity faActivity = (FragmentActivity) super.getActivity();
final LinearLayout linearLayout = (LinearLayout) inflater.inflate(R.layout.fragment__client, container, false);
addJob = (AddJob)getActivity();
clientList = (ListView) linearLayout.findViewById(R.id.listView);
clientList.setChoiceMode(ListView.CHOICE_MODE_SINGLE);
dbHandler = new DraycottDataHandler(super.getActivity().getApplicationContext());
if (dbHandler.getClientCount() != 0)
Clients.addAll(dbHandler.getAllClients()); //Loads clients into Client list
populateList(); //Sets adapter for the listview.
if(addJob.getEdit() == 1) { //Get edit mode from activity
NewJobClass editJob = addJob.getEditJob();
for (int i = 0; i < Clients.size(); i++) {
ClientClass client = Clients.get(i);
if (client.getID() == editJob.getClientID()) {
clientList.setItemChecked(i, true); //Highlight item (doesnt do anything).
}
}
}
clientList.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
selectedClient = Clients.get(position);
listener.getClientData(selectedClient);
}
});
return linearLayout;
}
ListView XML
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools" android:layout_width="match_parent"
android:layout_height="match_parent" android:paddingLeft="@dimen/activity_horizontal_margin"
android:paddingRight="@dimen/activity_horizontal_margin"
android:paddingTop="@dimen/activity_vertical_margin"
android:paddingBottom="@dimen/activity_vertical_margin"
android:orientation="vertical"
tools:context="com.simple.jack.application.Fragment_Client">
<ListView
android:layout_width="match_parent"
android:layout_height="match_parent"
android:id="@+id/listView"
android:choiceMode="singleChoice"
android:listSelector="#D3D3D3"
android:clickable="true"/>
</LinearLayout>
如果需要更多代码,我很乐意提供它。
这个问题与我的相似,但答案给了我一个InflateException。
提前感谢您的帮助。
答案 0 :(得分:0)
此时视图尚未就绪,请尝试发布:
linearLayout.post(new Runnable(){
@override
public void run(){
//your code that selects the item
}});
或在onViewCreated上调用它
答案 1 :(得分:0)
您确定正在调用clientList.setItemChecked(i, true);
吗?
您可以尝试添加代码以在onViewCreated
方法中进行选择。