我尝试使用MVVM创建一个带ListPickerFlyout
的自定义按钮。我希望达到的结果是这样的:
custom Button with ListPickerFlyout
我的问题是如何将SelectedItem
从ListPickerFlyout
绑定到内容TextBlock
。
我正在使用MVVM Light Windows Phone 8.1(Store Appp)。
我的Xaml代码:
<Button Background="White"
HorizontalAlignment="Stretch"
HorizontalContentAlignment="Stretch">
<Grid>
<Grid.ColumnDefinitions>
<ColumnDefinition Width="*" />
<ColumnDefinition Width="40" />
</Grid.ColumnDefinitions>
<!-- Content TextBlock -->
<TextBlock Text="{Binding MyVM.SelectedItem, Mode=TwoWay}"
Style="{StaticResource DefaultTextBlock}"
FontSize="22"
HorizontalAlignment="Left"
VerticalAlignment="Center"
Margin="10, 0, 0, 0"/>
<Image Height="20" Grid.Column="1"
VerticalAlignment="Center" HorizontalAlignment="Center"
Source="../Assets/icons/arrow_down.png"/>
</Grid>
<Button.Flyout>
<ListPickerFlyout PickerFlyoutBase.Title="$Items$"
ItemsSource="{Binding MyVM.listItems}"
SelectedItem="{Binding MyVM.SelectedItem, Mode=TwoWay}" >
<ListPickerFlyout.ItemTemplate>
<DataTemplate>
<StackPanel>
<TextBlock Text="{Binding}"
Style="{StaticResource DefaultTextBlock}"
FontSize="22"/>
</StackPanel>
</DataTemplate>
</ListPickerFlyout.ItemTemplate>
</ListPickerFlyout>
</Button.Flyout>
在MyVM中我有
public string SelectedItem { get; set; }
编辑:
解决了问题,我忘了添加RaisePropertyChanged("SelectedItem");
。
所以,在我的MVVM类中:
private string _selectedItem;
public string SelectedItem
{
get { return _selectedItem; }
set
{
if (_selectedItem != value)
{
_selectedItem = value;
RaisePropertyChanged("SelectedItem");
}
}
}
答案 0 :(得分:0)
只需要在MVVM类中添加RaisePropertyChanged("SelectedItem");
。
完整的代码:
private string _selectedItem;
public string SelectedItem
{
get { return _selectedItem; }
set
{
if (_selectedItem != value)
{
_selectedItem = value;
RaisePropertyChanged("SelectedItem");
}
}
}