我想使用swift和Parse从PFUser类中搜索名字和姓氏来关注和取消关注用户。我使用了UISearchController,但在输入时它没有检索用户。它只是在我按下回车时检索用户。 另一个问题,当我搜索用户时,它只是检索名字而不是姓氏。例如,当我搜索Sara John时,它找回了Sara John和Sara March。然而,当我输入M时,它也检索了Sara March。问题是没有检索到名字和姓氏!我该如何解决?
这是我的代码,我不知道我做错了什么,请帮忙。
func loadSearchUsers(searchString: String) {
let firstName = searchString
let lastName = searchString
let firstNameQuery:PFQuery = PFUser.query()!
firstNameQuery.whereKey("first_name", matchesRegex: "(?i)\(firstName)")
let lastNameQuery:PFQuery = PFUser.query()!
lastNameQuery.whereKey("last_name", matchesRegex: "(?i)\(lastName)")
let query = PFQuery.orQueryWithSubqueries([firstNameQuery, lastNameQuery])
self.searchActive = true
query.findObjectsInBackgroundWithBlock { (objects, error) -> Void in
//1
if let users = objects {
if (error != nil)
{
let myAlert = UIAlertController(title:"Error", message:error?.localizedDescription, preferredStyle:UIAlertControllerStyle.Alert)
let okAction = UIAlertAction (title: "OK", style: UIAlertActionStyle.Default, handler: nil)
myAlert.addAction(okAction)
self.presentViewController(myAlert, animated: true, completion: nil)
return
}
self.searchUsers.removeAll(keepCapacity: false)
self.userIds.removeAll(keepCapacity: false)
self.isFollowing.removeAll(keepCapacity: false)
//2
for object in users {
//3
if let user = object as? PFUser {
//4
if user.objectId! != PFUser.currentUser()?.objectId {
self.searchUsers.append(user)
self.userIds.append(user.objectId!)
self.tableView.reloadData()
let query = PFQuery(className: "followers")
query.whereKey("followFrom", equalTo: PFUser.currentUser()!.objectId!)
query.whereKey("followTo", equalTo: user.objectId!)
query.whereKey("status", equalTo:"followed")
query.findObjectsInBackgroundWithBlock({ (objects, error) -> Void in
if let objects = objects {
if objects.count > 0 {
self.isFollowing[user.objectId!] = true
} else {
self.isFollowing[user.objectId!] = false
}
}
if self.isFollowing.count == self.userIds.count {
self.tableView.reloadData()
self.searchActive = false
}
})
}
}}
}
}
}
// MARK: - Search Bar Delegate Methods
func searchBarSearchButtonClicked(searchBar: UISearchBar) {
let searchString: String = searchBar.text!.lowercaseString
// Force search if user pushes button
if (searchString != "") {
loadSearchUsers(searchString)
}else
{loadSearchUsers("")}
self.userSearchController.resignFirstResponder()
}
func searchBarCancelButtonClicked(searchBar: UISearchBar) {
searchActive = false
searchBar.text = ""
self.resultsController.tableView.reloadData()
}
func updateSearchResultsForSearchController(searchController: UISearchController) {
let searchString = String()
if searchString.lowercaseString.containsString(self.userSearchController.searchBar.text!.lowercaseString) {
if (searchString != "" && !self.searchActive) {
loadSearchUsers(searchString)
}
//Updates the results tableview
self.resultsController.tableView.reloadData()
}
}
func searchBarTextDidBeginEditing(searchBar: UISearchBar) {
searchActive = true
self.resultsController.tableView.reloadData()
}
答案 0 :(得分:0)
在您同时书写时使用以下方法进行搜索
func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String)
答案 1 :(得分:0)
我的建议是使用NSPredicate来简化您的搜索查询,并且b)合并为1个查询。
// Pseudo code - you will need to pad this out with all the Parse fripperies
let searchKey = "Sara"
let pre = NSPredicate(format: "first_name CONTAINS %@ OR last_name CONTAINS %@", argumentArray: [search_key, search_key])
let qry = PFQuery(className: "User", predicate: pre)
您需要调整此代码以适合您调用查询的方式 - 在后台或针对固定的本地数据。但我认为这会对你有帮助。
以下是关于如何使用Predicates的Parse指南的链接 - 我强烈建议使用它们。 https://www.parse.com/docs/ios/guide#queries-specifying-constraints-with-nspredicate
请记住 - 解析查询区分大小写。这意味着如果您的存储值=“Sara”,则搜索“sara”将失败。通常最好添加一个包含小写文本值的隐藏列 - 然后使用此列进行搜索。