编辑php中重复区域的动态数据

Question

我想编辑一个基于FileNo的记录集，该记录集与另一个以fileno作为链接字段的表链接。我在这里提供了两组代码，一组是工作，另一组是代码错误。

工作代码：

$sql="SELECT * FROM casedt WHERE AdvUser= '".$_SESSION['MM_Username']."' &&  FileNo = $fileno ";
$result= mysqli_query($link, $sql) or die ('Unable to run query:'.mysql_error());
#$count=mysqli_num_rows($result);
$row  = mysqli_fetch_array($result);

 echo "<table border='1'><tr><th>Adv User</th><th>File No.</th><th>Next Dt</th><th>Comments</th><th></th></tr>";
    // output data of each row
    while($row = mysqli_fetch_assoc($result)) 
    {
        echo "<tr><td>".$row["AdvUser"]."</td><td>".$row["FileNo"]."</td><td>".$row["NextDt"]."</td><td>".$row["Comments"]."</td></tr>";   

    }

非工作代码：

$sql="SELECT * FROM casedt WHERE AdvUser= '".$_SESSION['MM_Username']."' &&  FileNo = $fileno ";
$result= mysqli_query($link, $sql) or die ('Unable to run query:'.mysql_error());
#$count=mysqli_num_rows($result);
$row  = mysqli_fetch_array($result);

 echo "<table border='1'><tr><th>Adv User</th><th>File No.</th><th>Next Dt</th><th>Comments</th><th></th></tr>";
    // output data of each row
    while($row = mysqli_fetch_assoc($result)) 
    {
        echo "<tr><td>".$row["AdvUser"]."</td><td>".$row["FileNo"]."</td><td>".$row["NextDt"]."</td><td>".$row["Comments"]."</td><td><a href=EditDate.php?recordID= .$row['FileNo'] Edit</a></td</td></tr>";   

    }