我正在尝试创建一个登录表单,并且我已经选择在用户登录后修改用户的电子邮件ID。为此,我编写了以下代码。
char newmail[50];
cout<<"Enter New Email Id\n";
cin>>newmail;
fstream f2;
f2.open("db.txt" , ios::out |ios::ate| ios::binary);
strcpy(u.email,newmail);
f2.seekp(pos,ios::beg);
cout<<f2.tellp()<<endl;
f2.write((char*)&u, sizeof(user));
f2.close();
cout<<"Details edited sucessfully\n";
break;
问题在于:我登录。选择修改电子邮件ID的选项。输入新的。没有错误,细节编辑成功。然后,当我去检查用户列表(为此编写代码,完美工作)时,所有用户都无效,即他们的数据为空但仍占用空间,并且只有一条记录包含所有数据,是的是电子邮件修改了id。当我使用f2.seekp(-sizeof(u),ios::cur);
专门将指针设置在当前记录时,我无法弄清楚为什么所有数据都无效。
我已经交叉检查指针的位置,光标就在它的位置。
整个代码是这样的: -
#include<iostream>
#include<fstream>
#include<string.h>
#include<stdlib.h>
using namespace std;
class user
{public:
char username[50];
char password[50];
char email[50];
int reg()
{
cout<<"REGISTRATION FORM\n";
cout<<"Enter User name\n";
cin>>username;
cout<<"Enter Email\n";
cin>>email;
cout<<"Enter Password\n";
cin>>password;
}
int putdata()
{
cout<<"Username "<<username<<" "<<"Email ID "<<email<<endl;
}
char* retuser()
{
return username;
}
char* retpass()
{
return password;
}
char* retmail()
{
return email;
}
};
int main()
{int a=sizeof(user);
char ans;
int ch;
fstream f;
user u;
do
{
cout<<"MAIN MENU\n";
cout<<"ENTER 1 FOR NEW REGISTRATION\n";
cout<<"ENTER 2 TO LOGIN\n";
cout<<"ENTER 3 FOR MEMBER LIST\n";
cin>>ch;
if(ch==1)
{
u.reg();
f.open("db.txt", ios::app|ios::out|ios::binary);
f.write((char*)&u, sizeof(user));
f.close();
cout<<"Registration successful\n";
}
if(ch==2)
{
char uname[50];
char pass[50];
int flag=0;
cout<<"LOGIN\n";
cout<<"Enter Username and Password\n";
cin>>uname>>pass;
f.open("db.txt", ios::in | ios::binary);
f.read((char*)&u, sizeof(user));
while(f)
{
if(strcmp(u.retuser(),uname)==0)
{
if(strcmp(u.retpass(),pass)==0)
{
flag=1;
cout<<"Login Successful\n";
cout<<"USERNAME : -"<<u.retuser()<<endl;
cout<<"EMAIL ID : -"<<u.retmail()<<endl;
int pos;
pos=f.tellg();
pos=pos-a;
int i;
cout<<"Press 1 to modify email id, 2 to exit\n";
cin>>i;
if(i==1)
{
char newmail[50];
cout<<"Enter New Email Id\n";
cin>>newmail;
fstream f2;
f2.open("db.txt" , ios::out |ios::ate| ios::binary);
strcpy(u.email,newmail);
f2.seekp(pos,ios::beg);
cout<<f2.tellp()<<endl;
f2.write((char*)&u, sizeof(user));
f2.close();
cout<<"Details edited sucessfully\n";
break;
}
else if(i==2)
{
exit(0);
}
}
}
f.read((char*)&u, sizeof(user));
}
f.close();
if(flag==0)
{
cout<<"Wrong username or password\n";
}
}
if(ch==3)
{
cout<<"MEMBER LIST\n";
f.open("db.txt", ios::in | ios::binary );
f.read((char*)&u, sizeof(user));
while(f)
{
u.putdata();
f.read((char*)&u, sizeof(u));
}
f.close();
}
cout<<"Enter y to go to main menu\n";
cin>>ans;
}while(ans=='y' || ans=='Y');
}
答案 0 :(得分:0)
为了能够在正确的位置修改文件,您应该打开文件(一次)进行输入和输出。我将只向您展示管理邮件地址更改的部分代码,即使您应该改进代码并在许多其他部分添加一些用户输入检查。
if(ch==2) // I'd prefer a switch() here
{
char uname[50];
char pass[50];
int flag=0;
cout << "LOGIN\n";
cout << "Enter Username and Password\n";
cin >> uname >> pass;
fstream f("db.txt", ios::in | ios::out| ios::binary);
if ( f.bad() ) {
cout << "Error, unable to open users database file.";
exit(1);
}
// check the position BEFORE reading the user
int pos = f.tellg();
while( f.read((char*)&u, sizeof(user)) ) {
if( strcmp(u.retuser(),uname) == 0
&& strcmp(u.retpass(),pass) == 0 ) {
flag = 1;
cout << "Login Successful\n";
cout << "USERNAME : -"<<u.retuser()<<endl;
cout << "EMAIL ID : -"<<u.retmail()<<endl;
int i;
cout << "Press 1 to modify email id, 2 to exit\n";
cin >> i;
if( i == 1 ) {
char newmail[50];
cout << "Enter New Email Id\n";
cin >> newmail;
strcpy(u.email,newmail);
f.seekp(pos,ios::beg);
f.write((char*)&u, sizeof(user));
cout << "Details edited sucessfully\n";
break;
} else if ( i == 2 ) {
exit(0);
}
}
pos=f.tellg();
}
f.close();
if ( flag == 0 ) {
cout << "Wrong username or password\n";
}
}