我有一个用于检查键盘输入的Java代码。 如果特定字符返回True,则有一个循环。 对于任何其他角色,else返回false。
如何编写一个代码,用于识别程序选择上述两个(True或False)中的哪一个并打印出来? 实例connectionStatus
的布尔值import java.util.Scanner;
public class BlueTooth3 {
public boolean connectionStatus;
boolean connectBlueTooth () {
System.out.println("Enter connecting code Baby3");
Scanner keyboard = new Scanner(System.in);
String conCode = keyboard.next();
System.out.println("You Entered " + conCode);
keyboard.close();
if (conCode.equals ("c")){
System.out.println(conCode + " Is a true Code");
System.out.println("This is Boolean " +Boolean.TRUE);
return connectionStatus;
}
if (conCode.equals ("C")){
System.out.println(conCode + " Is a true Code");
System.out.println("This is Boolean " +Boolean.TRUE);
return connectionStatus;
}
else {
System.out.println( conCode + " Is a false Code" );
System.out.println("This is Boolean " + Boolean.FALSE);
return connectionStatus;
}
}
}
答案 0 :(得分:0)
除非我闭上眼睛,否则你似乎没有对connectionStatus
变量做任何事情。您可以更改该变量的值,以便接收该变量的函数可以相应地执行操作。例如:
if (conCode.equals ("C")){
System.out.println(conCode + " Is a true Code");
System.out.println("This is Boolean " +Boolean.TRUE);
connectionStatus = true; // means that the code went in this if
return connectionStatus;
}
else {
System.out.println( conCode + " Is a false Code" );
System.out.println("This is Boolean " + Boolean.FALSE);
connectionStatus = false; // means that the code went in this else
return connectionStatus;
}
你的代码应该是这样的:
public void myFunc(){
System.out.println(connectBlueTooth);
}
这只是简单地打印出connectBlueTooth
函数的结果,如果它进入if
则该结果为True,如果进入else
则为False。