Question

我有一个函数可以在ng-repeat中返回一个值。它基本上为ng-repeat的每个对象创建一个总数。

如何将每个返回值推送到新数组？我尝试过以下方法：

 $scope.lineTotal = function(line){
    var markup = 1 + (line.markupPct / 100);
    var discount = 1 - (line.discountPct / 100);

    var lineTotal = line.price * discount * markup * line.qty;

    return lineTotal;

    $scope.newArray.push(lineTotal);
}

Answer 1

public class Main {

public static void main(String[] args) {
// write your code here
    int size = 8;
    int[][] matrix = new int[size][size];
    for (int i = 0; i < size ; i++) {
        for (int j = 0; j < size; j++) {

            matrix[i][j] = (i+(2*j));
        }
    }
    trace(matrix, size);
    rotate(matrix);
    System.out.println("________________________");
    trace(matrix, size);

}

public static void rotate(int[][] matrix){
    int stop = matrix.length -1;

    rotate(matrix, stop, 0);
}

public static void rotate(int[][] matrix, int stop, int start){

    if(start - stop == 1) return;

    int [] temp = new int[stop-start];

    //save top row in an array
    for (int i = 0; i < stop-start ; i++) {
        temp[i] = matrix[start][start+i+1];
    }
    //System.out.println(Arrays.toString(temp));

    //left goes to top
    for (int i = start; i < stop ; i++) {
        matrix[start][start+stop-i] = matrix[i][start];
    }

    //bottom goes to left
    for (int i = start; i < stop ; i++) {
        matrix[i][start] = matrix[stop][i];
    }

    //right goes to bottom
    for (int i = start; i < stop ; i++) {
        matrix[stop][i] = matrix[start+stop-i][stop];
    }

    //temp array goes to right
    for (int i = 0; i < temp.length ; i++) {
        matrix[start + i + 1][stop] = temp[i];
    }

    rotate(matrix, stop-1, start + 1);
}



public static void trace(int[][] matrix, int size){
    for (int i = 0; i < size; i++) {
        for (int j = 0; j < size ; j++) {
            System.out.printf("%2d ", matrix[i][j]);

        }
        System.out.println();
    }
}

在ng-repeat内将函数值推送到数组

1 个答案: