Question

我正在使用primefaces 5.3运行Glassfish 4，EclipseLink 2.5。当我将事件发布到primefaces事件总线并尝试更新我的datagrid组件时，它将在提交浏览器中更新，但在单独的会话（第二个用户）中，更新失败，我在浏览器控制台中看到以下错误：

WebSocket connection to 'ws://localhost:8080/myapp/primepush/notify?X-
Atmosphere-tracking-id=0&X-Atmosphere-Framework=2.2.12-javascript&   
X-Atmosphere-Transport=websocket&X-Atmosphere-TrackMessageSize=true&
X-atmo-protocol=true' failed: Error during WebSocket handshake: 
Unexpected response code: 200
push.js.xhtml?ln=primefaces&v=5.3:1 Websocket closed, reason: 
Connection   was closed abnormally 
(that is, with no close frame being   sent). - wasClean: false

我也看到服务器上抛出此异常：

Warning: StandardWrapperValve[Push Servlet]: 
Servlet.service() for  servlet Push Servlet threw exception
java.io.IOException: 
java.util.concurrent.TimeoutException

我通过这样做解雇了这个事件：

EventBus eventBus = EventBusFactory.getDefault().eventBus();
eventBus.publish("/notify", "price");

EventBus eventBus = EventBusFactory.getDefault().eventBus();
eventBus.publish("/notify", "order");

然后我在javascript中处理这些并通过remotecommand更新：

<script type="text/javascript">
            function handleMessage(data) 
            {
                console.log("handle message fired")
                console.log(data);
                if(data == 'order')
                {
                    console.log("data is order");
                    checkOrders();
                }

                if(data == 'price')
                {
                    console.log("data is price");
                    updateWidget();
                    updateBalance();
                }
            } 
    </script>

<p:remoteCommand name="updateWidget"
             actionListener="#{parliamentManager.findLatestPrices}"
             update="prices"
             autoRun="true"/>

<p:remoteCommand name="updateBalance"
             actionListener="#{parliamentManager.findTraders}"
             update="balance"
             autoRun="true"/>

<p:remoteCommand name="checkOrders"
             actionListener="#{parliamentManager.checkOrders}" /> 
</h:form>
<p:socket onMessage="handleMessage" channel="/notify" />

这是我的datagrid组件：

<h:panelGroup id="resultDisplay">                          
            <p:dataGrid id="prices" var="orderBooks" value=
            "#{parliamentManager.latestPricesResults}" columns="3" rows="12">
                <p:column>
                <p:panel header="#{orderBooks.bidOrderId.member.memberId}">
            <h:panelGrid columns="1">
            <h:outputText value="#{orderBooks.price}" />
            </h:panelGrid>
            </p:panel>
            </p:column>
        </p:dataGrid>

要返回我的开头段落，为什么我对datagrid组件的更新在提交浏览器中成功，但在另一个示例中更新失败，我看到错误消息？

Answer 1

我通过将我的Glassfish版本更新为4.1.1（版本1）解决了这个问题，原始版本已经很老了（2014）。

p：套接字在WebSocket握手期间出错：意外的响应代码：200

1 个答案: