如何将“方形”和“矩形”对象显示为实际形状？

Question

我为练习问题制作了两个'square'和'rect'对象。但现在我想尝试将它们显示为实际形状。我可以用物体做这个吗？如果是这样的话？或者我将别无选择，只能使用rect（）;方法

这是我的代码片段，显示了对象属性。 更新：添加其余代码以便更好地理解。

// Determines the 'shapeType' depending on the perimeters.
var shapeType = function (shape) {

  if ( shape.height === shape.width ) {
    shape.shapeType = "square";

  } else if ( shape.height != shape.width ) {
    shape.shapeType = "rectangle";

  }
};


// Used to change height and width of the quad.
var quadSize = function (newHeight, newWidth) {
  this.height = newHeight;
  this.width = newWidth;
};


// Checks both objects 'rect' / 'square' to determine the perimeter's are     proper.
var shapeWrapper = function (shape) {

  if ( shape === square ) {
    if ( shape.height != shape.width ) {
      console.log("ERROR: Object 'square' is outputed as a rectangle.");
    }

  } else if ( shape === rect ) {
    if ( shape.height === shape.width ) {
      console.log("ERROR: Object 'rect' is outputed as a square.");
    }

  }
};

var square = {
  objName: "square"
};
square.quadSize = quadSize;
square.quadSize(42, 42);
square.shapeType = shapeType;
square.shapeType(square);

var rect = {
  objName: "rect"
};
rect.quadSize = quadSize;
rect.quadSize(42, 24);
rect.shapeType = shapeType;
rect.shapeType(rect);


// Outputs objects 'rect' and 'square'
console.log(square);
console.log(rect);
// Outputs an ERROR if the shapes perimeters are improper.
shapeWrapper(square);
shapeWrapper(rect);

谢谢！