Question

我正在尝试将一段代码从Java转换为C并且我被困在这里，试图在每个位置获得一个角色。

char ch;

line += ' ';
    while (pos < line.length()) 
    {
      ch = line.charAt(pos);  
...

C中有什么类似的东西可以将行ch = line.charAt(pos)从java转换为C吗？

Answer 1

您可以像使用String一样访问值。

public class Logic {

    private int position = 1;

    public void appendPosition(){
        // When debugging strange stuff, 
        // keep each step simple. 
        // Is calculatePosition working as it should?
        int newPosition = calculatePosition(this.position);
        this.position = newPosition;
    }

    // Always use parameters as final. It's good karma.
    // You don't NEED to declare them as final,
    // but let's try to be EXTRA clear.
    private int calculatePosition(final int targetPosition){

        // Yes, make as much as you can immutable
        // You'll save a ton of mental bandwidth.
        final int localCopy = targetPosition +6;

        if(snakeLocations[localCopy]>0) {
            return (localCopy -6);
            // Don't force the maintenance programmer to 
            // read all your stuff. Return often, return early. 
            // This isn't Cc++, where you need to 
            // actually free your reference/pointers, 
            // so there's no point enforcing a single return.
        }
        if(ladderLocations[localCopy]>0) {
            return (localCopy+6);
        }
        return localCopy;
    }
}

Answer 2

你可以通过这种方式获得特定位置的角色

What file would you like to count the lines of code for?
Counting lines in test1.txt...
// This comment should not count
This file now has two lines of code
// Another comment that shouldn't be counted
}
A total of 4 lines should be counted.
3

但是当你有一个指针数组时：

char str[] = "Anything";
printf("%c", str[0]);

如果您需要更改字符串，请使用

char* an_array_of_strings[]={"balloon", "whatever", "isnext"};
cout << an_array_of_strings[1][2] << endl;

来源：here

Answer 3

在C中，从字符数组中获取字符的最简单方法（I.E. a string）

根据您发布的代码中的变量，

char ch;

line += ' ';
while (pos < line.length()) 
{
    ch = line.charAt(pos);  
...

假设字符串以NUL字节（'\ 0'）
假设line[]数组中有另一个角色的空间

会变成：

#include <string.h>
strcat( line, " ");
size_t maxPos = strlen( line );
for( pos = 0; pos < maxPos; pos++ )
{
    ch = line[pos];
....

有没有类似于Java的字符串'charAt（）'方法在C？

3 个答案: