Question

我对编程很新，所以如果这是一个非常无聊的问题我会道歉。我正在创建一个基本的，多选择类型的游戏，但我遇到了一个问题。当我在switch循环中执行我的代码时（在void shop（）中），我得到一个常量＆＃34;这不是一个有效的选项。请再试一次＆＃34;即使我输入1,2,3或4.如果你帮助我，我将非常感激。谢谢！

#include <iostream>
#include <iomanip>
#include <string>

 using namespace std;

 bool stoleSomething = false;
 string choice = " "; //we will use this choice to manipulate leaving buildings and what-not

void shop(void);
void arena(void);
void inn(void);

int main(){

cout << "You enter the town and see three main areas: the Arena, the Shop and the Inn\n";
cout << "Where do you want to go? Type the name of the location that you want to go - (*no caps* 'arena', 'shop' or 'inn'): \n";

while (choice != "arena" && choice != "shop" && choice != "inn"){
    cin >> choice;
    if (choice == "arena"){
        arena();
    }
    else if (choice == "shop"){
        shop();
    }
    else if (choice == "inn"){
        inn();
    }
    else{
        cout << "That is not a valid choice, please try again. \n";
    }
}

system("pause");
}



void shop(){
int choice_shop = 0;
static int isDrunk = 0;

cout << "Here are the things that you can do in the shop: \n";
cout << "1. Have a drink \n";
cout << "2. Repair equipment \n";
cout << "3. Steal something \n";
cout << "4. Leave \n";

while (choice_shop != 4){
    cout << "Enter the option number of the action that you want to take: ";
    cin >> choice;

    switch (choice_shop){
    case 1: cout << "You feel a bit more tipsy. \n";
        isDrunk += 1;
        break;
    case 2: cout << "your equipment is fully repaired. \n";
        break;
    case 3: cout << "You hear the shop owner yell at you, and you become frightened; you cannot enter the shop again. \n";
        stoleSomething = true;
        choice = " ";
        break;
    case 4: choice = " ";
    default: cout << "That is not a valid option. Please try again. \n";
    }
    if (isDrunk == 5){
        cout << "You have drunk so much that you finally black out. \n";
        cout << "You wake up just outside of the town. \n";
        choice = " ";
    }
}

 }

 void arena(){
//these will be filled later
 }

 void inn(){
//this will be filled later
 }

Answer 1

您有一个基于while的{{1}}循环和switch语句，该语句仍然初始化为choice_shop。

Answer 2

choice_shop设置为0，您从未更改过它。所以它始终是Switch（choice_shop）的默认情况。你真的打算用'cin＆gt;＆gt; choice_shop＆＃39;在void商店（）???

Answer 3

在输入

之前，您需要让用户修改您的choice_shop变量

切换功能输入无效（C ++）

3 个答案: