Question

我有一张看起来像这样的桌子。该表是通过每天ping系统中的每个帐户来生成的，以记录“mrr”。量。＆＃39; mrr＆＃39;如果帐户未付款，则帐户为0。它会在帐户开始付款时记录一个值。如果帐户取消，则记录的mrr将返回0.

+-----------+------------+------------+-----+
| paylog_id | account_id |    date    | mrr |
+-----------+------------+------------+-----+
|      1001 |         99 | 2016-01-15 |   0 |
|      1002 |         99 | 2016-01-16 |   0 |
|      1003 |         99 | 2016-01-17 |   0 |
|      1004 |         99 | 2016-01-18 |   0 |
|      1005 |         99 | 2016-01-19 |   0 |
|      1006 |         99 | 2016-01-20 |  25 |
|      1007 |         99 | 2016-01-21 |  25 |
|      1008 |         99 | 2016-01-22 |  25 |
|      1009 |         99 | 2016-01-23 |  25 |
|      1010 |         99 | 2016-01-24 |  25 |
|      1011 |         99 | 2016-01-25 |  25 |
|      1012 |         99 | 2016-01-26 |  25 |
|      1013 |         99 | 2016-01-27 |  25 |
|      1014 |         99 | 2016-01-28 |   0 |
|      1015 |         99 | 2016-01-29 |   0 |
|      1016 |         99 | 2016-01-30 |   0 |
|      1017 |         99 | 2016-01-31 |   0 |
|      1018 |         99 | 2016-02-01 |   0 |
|      1019 |         79 | 2016-02-23 | 255 |
|      1020 |         79 | 2016-02-24 | 255 |
|      1021 |         79 | 2016-02-25 | 255 |
|      1022 |         79 | 2016-02-26 | 255 |
|      1023 |         79 | 2016-02-27 | 255 |
|      1024 |         79 | 2016-02-28 |  50 |
|      1025 |         79 | 2016-02-29 |  25 |
|      1026 |         79 | 2016-03-01 |  25 |
|      1027 |         79 | 2016-03-02 |  27 |
+-----------+------------+------------+-----+

我需要知道两条信息 -

帐户开始付款的第一个日期的金额是多少？
帐户开始付款的当月最后一天的金额是多少？

以上示例中的结果应为：

+-----------+------------+------------+-----+------------+-------------+------------+------+
| paylog_id | account_id |    date    | mrr | paylog_id1 | account_id1 |   date1    | mrr1 |
+-----------+------------+------------+-----+------------+-------------+------------+------+
|      1006 |         99 | 2016-01-20 |  25 |       1017 |          99 | 2016-01-31 |    0 |
|      1018 |         79 | 2016-02-23 | 255 |       1024 |          79 | 2016-02-29 |   25 |
+-----------+------------+------------+-----+------------+-------------+------------+------+

我知道我可以使用此查询获得第一个付款日期：

SELECT
 a.paylog_id,
 a.account_id,
 a.date,
 a.mrr
FROM
 ds_paylogs a
INNER JOIN (
 SELECT
  account_id,
  min(date) mdate, mrr
 FROM
  ds_paylogs b
where b.mrr >0
 GROUP BY
  account_id
) b ON a.account_id = b.account_id
AND a.date = b.mdate

结果：

+------+----+----------+-----+
| 1006 | 99 | 20-01-16 | 25  |
+------+----+----------+-----+
| 1018 | 79 | 23-02-16 | 255 |
+------+----+----------+-----+

另外，我可以使用以下方式在第一个付款日期获得当月的最后一天：

SELECT
 a.paylog_id,
 a.account_id,
 a.date,
 a.mrr
FROM
 ds_paylogs a
INNER JOIN (
 SELECT
  account_id,
  LAST_DAY(min(date)) mdate, mrr
 FROM
  ds_paylogs b
where b.mrr >0
 GROUP BY
  account_id
) b ON a.account_id = b.account_id
AND a.date = b.mdate

结果：

+------+----+----------+----+
| 1017 | 99 | 31-01-16 | 0  |
+------+----+----------+----+
| 1024 | 79 | 29-02-16 | 25 |
+------+----+----------+----+

我想将这两个结果合并为一个视图。我被困在怎么办？

非常感谢有关如何操作或如何简化查询的任何建议。

更新：执行以下操作可以获得我所需要的内容。但是，似乎应该有一个更优雅的解决方案。

SELECT
    *
FROM
    (
        SELECT
            a.paylog_id,
            a.account_id,
            a.date,
            a.mrr
        FROM
            ds_paylogs a
        INNER JOIN (
            SELECT
                account_id,
                min(date) mdate,
                mrr
            FROM
                ds_paylogs b
            WHERE
                b.mrr > 0
            GROUP BY
                account_id
        ) b ON a.account_id = b.account_id
        AND a.date = b.mdate
    ) q
INNER JOIN (
    SELECT
        a.paylog_id,
        a.account_id,
        a.date,
        a.mrr
    FROM
        ds_paylogs a
    INNER JOIN (
        SELECT
            account_id,
            LAST_DAY(min(date)) mdate,
            mrr
        FROM
            ds_paylogs b
        WHERE
            b.mrr > 0
        GROUP BY
            account_id
    ) b ON a.account_id = b.account_id
    AND a.date = b.mdate
) r ON q.account_id = r.account_id

自我加入以获得第一个记录并记录在月的最后一天

0 个答案: