PHP和fopen（），有时工作有时会失败（上次回答“资源ID＃17”）

Question

我已经尝试了一个名为throw cronjobs的长脚本解决方案和超时问题（事实上我需要恢复大量数据并将其存储在数据库中，每天4次）。

所以我创建了一个php页面，使用fopen（），使用不同的vars多次调用相同的文件，以便接收文件选择\不同的数据部分并存储它们。

我使用fopen（）就像文件的10倍。

以下是该脚本的一部分：

 function call() {

     $time_start_insert = microtime(true);
     $server = "servername";

     // ***********  *********** OPEN PROCESSES lvl 1 ***********  
     echo "<div><br><i>************ Jobs Market Insert ************</i></div><br>";
     echo "<br><div><i>************ Server $server lvl 1 ************</i></div><br>";
     // ***********  *********** OPEN PROCESSES lvl 1 ***********       
     // open child process
     echo "<br><i><p class='start'>************ Lunched process 0-10 lvl 1 ************</i></p>";
     $numC = "10";
     $fromC = "0";
     $workSkill = "1";
     $fileName = urlencode("".ucfirst($server)." Job $fromC-$numC lvl $workSkill"); 
     $url = "http://URL.../dbjob.php?server=$server&csel=$numC&cfn=$fromC&joblevel=$workSkill&fname=$fileName";
     echo "<br>";
     print_r($url);     
     $child1j10 = fopen($url, 'r') or die("<br>Couldn't get file, so I'll retry<br>".print_r($url)."<br>".fopen($url, 'r'));
     echo_flush();

     // Output one line until end-of-file
     if($child1j10) {
        $buffer = stream_get_contents($child1j10);
        echo "<br>";
        echo "<br><b><p class='titles'>++++++++++++++This is response from process:++++++++++++++++++</b></p>";
        print_r($buffer);
        echo "<br><b><p class='endtitles'>--------------FINISHED process called job 10 lvl 1 --------------</b><br></p>";
        fclose($child1j10);
   }    
   echo_flush();

   // open child process
   echo "<br><i><p class='start'>************ Lunched process 10-20 lvl 1 ************</i></p>";
   $numC = "10";
   $fromC = "10";
   $workSkill = "1";
   $fileName = urlencode("".ucfirst($server)." Job $fromC-".($fromC+$numC)." lvl $workSkill");  
   $url = "http://URL/dbjob.php?server=$server&csel=$numC&cfn=$fromC&joblevel=$workSkill&fname=$fileName";
   echo "<br>";
   print_r($url);       
   $child1j20 = fopen($url, 'r') or die("<br>Couldn't get file, so I'll retry<br>".print_r($url)."<br>".fopen($url, 'r'));
   echo_flush();

   // Output one line until end-of-file
   if($child1j20) {
        $buffer = stream_get_contents($child1j20);
        echo "<br>";
        echo "<br><b><p class='titles'>++++++++++++++This is response from process:++++++++++++++++++</b></p>";
        print_r($buffer);
        echo "<br><b><p class='endtitles'>--------------FINISHED process called job 20 lvl 1 --------------</b><br></p>";
   fclose($child1j20);
   }    
   //stream_set_timeout($child1j40, 2700);
   echo_flush();

所以我推出了这个页面，它适用于ex。 6次，比回报我：

 //from fist print_r
 http://URL/dbjob/dbjob.php?server=primera&csel=10&cfn=60&joblevel=2&fname=Primera+Job+60-70+lvl+2
 //from second print_r
 http://URL/dbjob.php?server=primera&csel=10&cfn=60&joblevel=2&fname=Primera+Job+60-70+lvl+2
 Couldn't get file, so I'll retry
 1
 Resource id #17    

你知道为什么吗？ THX。