在给定的代码中 - 虽然识字 fgets
的输入值工作正常,但是当我们使用printf给出输出时,它不会给出预期的输出(空格输出)。
有谁可以帮我解决这个问题?
BTW我正在使用 Visual Studio 2015 来调试我的代码。
#include <stdio.h>
#include <stdlib.h>
#include <process.h>
//GLOBAL-VARIABLE DECLARTION
#define MAX 1000
//GLOBAL-STRUCTURES DECLARATION
struct census {
char city[MAX];
long int p;
float l;
};
//GLOBAL-STRUCTURE-VARIABLE DECLARATION
struct census cen[MAX] = { 0 };
//USER-DEFINED FUNCTION
void header();
void header() {
printf("*-*-*-*-*CENSUS_INFO*-*-*-*-*");
printf("\n\n");
}
//PROGRAM STARTS HERE
main() {
//VARIABLE-DECLARATION
int i = 0, j = 0;
char line[MAX] = { 0 };
//int no_of_records = 0;
//FUNCTION CALL-OUT
header();
printf("Enter No. of City : ");
fgets(line, sizeof(line), stdin);
sscanf_s(line, "%d", &j);
printf("\n\n");
printf("Enter Name of City, Population and Literacy level");
printf("\n\n");
for (i = 0; i <= j - 1; i++) {
printf("City No. %d - Info :", i + 1);
printf("\n\n");
printf("City Name :");
fgets(cen[i].city, MAX, stdin);
printf("\n");
printf("Population : ");
fgets(line, sizeof(line), stdin);
sscanf_s(line, "%d", &cen[i].p);
printf("\n");
printf("Literacy : ");
fgets(line, sizeof(line), stdin);
sscanf_s(line, "%d", &cen[i].l);
printf("Literacy : %f", cen[i].l);
printf("\n");
printf("_____________________________________");
printf("\n\n");
}
printf("*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-* ");
printf("Census Information");
printf(" *-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*-*");
printf("\n\n");
for (i = 0; i <= j - 1; i++) {
printf("City No. %d - Info :", i + 1);
printf("\n\n");
printf("City Name : %s", cen[i].city);
printf("\n");
printf("Population : %d",cen[i].p);
printf("\n");
printf("Literacy : %f", cen[i].l);
printf("\n");
printf("_____________________________________");
printf("\n\n");
}
//TERMINAL-PAUSE
system("pause");
}
答案 0 :(得分:3)
您的scanf有一个%d
,它应该是%f
。尝试更改您的代码:
printf("Literacy : ");
fgets(line, sizeof(line), stdin);
sscanf(line, "%f", &cen[i].l); /* <---- This line ---- */
printf("Literacy : %f", cen[i].l);
printf("\n");
%d
查找整数,但您将l
定义为浮点数,因此%f
是正确的格式。