每次实例化类的新实例时,我都会尝试自动增加属性值。这是我的类构造函数看起来的东西(我把它抽象了一下):
var Playlist = function(player, args){
var that = this;
this.id = ?; //Should auto increment
this.tracks = [];
this.ready = false;
this.unloaded = args.length;
this.callback = undefined;
this.onready = function(c){
that.callback = c;
};
this.add = function(tracks){
for(var i = 0; i < tracks.length; i++){
this.tracks.push(tracks[i]);
this.resolve(i);
}
};
this.resolve = function(i){
SC.resolve(that.tracks[i]).then(function(data){
that.tracks[i] = data;
if(that.unloaded > 0){
that.unloaded--;
if(that.unloaded === 0){
that.ready = true;
that.callback();
}
}
});
};
player.playlists.push(this);
return this.add(args);
};
var playlist1 = new Playlist(player, [url1,url2...]); //Should be ID 0
var playlist2 = new Playlist(player, [url1,url2...]); //Should be ID 1
我不想定义一个在全局范围内递增的初始变量。任何人都可以向我暗示正确的方向吗?干杯!
答案 0 :(得分:2)
您可以使用IIFE创建一个可以递增的私有变量。
var Playlist = (function() {
var nextID = 0;
return function(player, args) {
this.id = nextID++;
...
};
})();
答案 1 :(得分:0)
您可以在代码中的某处设置Playlist.id = 0
,然后在构造函数中将其递增,并将新值分配给实例属性,如:this.id = Playlist.id++
。
这是因为它没有很好地封装,所以它可能被滥用。
否则,我要提出Mike C所描述的解决方案,但他已经设定了一个包含这样一个想法的好答案,所以......