Question

所以基本上我在我的模型中有一个TIMESTAMPDIFF查询来确定持续时间，我希望它在视图中显示持续时间。问题是，它会显示错误。

请帮帮我，谢谢。

这是我的模型查询（model_attendance.php）：

public function getOne($username){
        $sql = "SELECT empnum FROM employees WHERE username='$username'";

        $result = $this->db->query($sql);

        $sql1 = "SELECT a.empnum,CONCAT(a.name,' ',a.midname,' ',a.lastname) AS
                NAME,CONCAT(b.indate,' ',b.intime) AS 'TIMEIN',CONCAT(b.outdate,'
                ',b.outtime)AS 'TIMEOUT', TIMESTAMPDIFF(HOUR, 'TIMEIN','TIMEOUT') AS 'DUR' 
                FROM employees AS a
                JOIN times AS b ON (a.empnum=b.userid)
                WHERE b.indate BETWEEN
                DATE(CONCAT(YEAR(CURRENT_TIMESTAMP),'-',MONTH(CURRENT_TIMESTAMP),'-','01'))
                AND DATE(LAST_DAY(CURRENT_TIMESTAMP)) AND b.userid='".$result->row(0)->empnum."'";

        $query = $this->db->query($sql1);

        return $query->result();
    }

Answer 1

要解决此问题，您需要将返回类型传递为＆＃34; false＆＃34;到活动记录选择查询。

$this->db->select("TIMESTAMPDIFF(YEAR,a.date_birth, CURDATE()) AS age", false);

Answer 2

将其分配给变量并将其传递给SQL Query。

    .centerSectionDivs{
      margin:0 auto;
    }

Answer 3

它可能是一个错误。我还没有检查过Query Builder类。但要解决这个问题......您可以尝试将`添加到像这样的列

$this->db->select("TIMESTAMPDIFF(YEAR, `a.date_birth`, CURDATE()) AS age");

或

$this->db->query("TIMESTAMPDIFF(YEAR, `a.date_birth`, CURDATE()) AS age");

TIMESTAMPDIFF无法处理codeigniter中的mysql查询

3 个答案: