查找所有合着者 - 面向/分组的多对多映射表

Question

Table : Books 
-------------
ID    Name
1     Book1
2     Book2
3     Book3
4     Book4

Table : Authors 
-------------
ID    Name
1     Author1
2     Author2
3     Author3
4     Author4


Table :  BookAuthorMapping
---------------------------
ID    BookId    AuthorId
1     1         1
2     1         2
3     1         3
4     2         2
5     2         3
6     3         3
7     4         4  

所以，

• Book1由Author1，Author2，Author3
撰写
• Book2由Author2，Author3
撰写
• Book3仅由Author3
撰写
• Book4仅由Author4
撰写

问题是： 鉴于AuthorId，我需要找出其他作者与他共同撰写了多少本书：

示例：

Given AuthorId: 1
-------------------
AuthorId   Count 
2          1           // 2 has co-authored only book1
3          1           // 3 has co-authored only book1
1          1           // Its okay, if i get author1 in the result

Given AuthorId: 2
-------------------
AuthorId   Count 
1          1           // 1 has co-authored only book1
3          2           // 3 has co-authored book1 and book2
2          2           // Its okay if i get author 2 in the result

Given AuthorId: 3
-------------------
AuthorId   Count 
1          1          // 1 has co-authored only book1
2          2          // 2 has co-authored book1 and 2
3          3          // Its okay if i get author 3 in the result.

Given AuthorId: 4
-------------------
AuthorId   Count 
4          1     // I should not get author1 0 author2 0 , author3 0 for this

- 编辑 - 我有一个像select aId, count(mapping.bId) from mapping join (select bId from mapping where aId = ?) as tmp on mapping.bId = tmp.bId group by aId;

这样的解决方案

此外，@ Giorgos Betsos在回复中提到了相同的内容。

如果没有内部查询，我很好奇。

Answer 1

试试这个：

SELECT "AuthorId", COUNT(*)
FROM BookAuthorMapping
WHERE "BookId" IN (SELECT "BookId" FROM BookAuthorMapping WHERE "AuthorId" = 1)
GROUP BY "AuthorId"

Demo here

您也可以使用INNER JOIN：

SELECT t1."AuthorId", COUNT(*)
FROM BookAuthorMapping AS t1
INNER JOIN BookAuthorMapping AS t2 ON t1."BookId" = t2."BookId" AND t2."AuthorId" = 1
GROUP BY t1."AuthorId"

Demo here

Answer 2

您也可以使用窗口功能执行此操作：

select authorid, count(*)
from (select bam.*,
             max(case when AuthorId = 1 then 1 else 0 end) over (partition by bookid) as HasAuthor1
      from BookAuthorMapping bam
     ) bam
where hasAuthor1 = 1
group by authorid;

在某些情况下，窗口函数会比使用join或in的方法更快。