Question

我想通过id在同一个<div>组中显示数据。我该怎么做呢？请参考图片，因为我解释不好。

这是我尝试过的一些代码。我不知道该怎么做

<?php 

$result = $mysqli->query("SELECT tblstudent.studentId,tblstudent.programme,tblstudent.cgpa,tblpersonalinfo.studentId,tblpersonalinfo.pImage,tblpersonalinfo.pImageType,tblpersonalinfo.pImageSize,tblpersonalinfo.pName,tblskill.skill FROM tblstudent INNER JOIN tblpersonalinfo ON tblstudent.studentId = tblpersonalinfo.studentId INNER JOIN tblskill ON tblpersonalinfo.studentId = tblskill.studentId ".$where_sql."  ");

  if ($result->num_rows != 0) {

      echo "<table class='scroll' width='700' border='0' bgcolor='#FF00FF' align='left'>";
      echo "<tbody>";

     while($row = mysqli_fetch_array($result)) {


 // get data from db


  echo "<input type='hidden' name='id' value='".$row[0]."'>";
  echo "<tr>";
  echo "<td>";
  echo '<div  class="title bg-primary" align="left" style="font-weight: bold;">' .   '&nbsp;' . '<img src="uploads/' . $row['pImage'] .' " alt = "avatar" height="60" width="50" >' . '&nbsp;' . $row['pName'] .  '</div>';
  echo '<div  align="left" class="sub">' . '<br>' . $row['programme']. '</div>';

  if ($row[0] == $row[0] ) {

  echo "<table class='scroll' width='700' border='1' bgcolor='#FF00FF' align='left'>";
  echo "<tbody>";
  echo "<tr>";
  echo "<td>";
  echo '<div  align="left" class="sub">' . '<br>' . $row['skill']. '</div>';
  echo "</td>";
  echo "</tr>";
  echo "</tbody>";
  echo "</table>";
  }
 }
 }
?>

Answer 1

您必须预处理查询结果。像这样：

$user = array();
while( $row = mysqli_fetch_array($result) )
{
    if( !isset($user['id']) )
    {
        $user['id'] = $row['studentId'];
        // Add here all the other fields you want
        $user['prg'] = array();
    }
    $user['prg'][] = array( 'skill'=>$row['skill'], 'proficiency'=>$row['proficiency'] );
}

您可以输出表格：

echo '<table>';
(...)
foreach( $user['prg'] as $prg )
{
    echo '<tr>';
    echo "<td>{$prg[skill]}</td>";
    echo '</tr>';
}
(...)
echo '</table>';

说明：

通过SQL查询，您可以获得多行，包含重复字段（用户ID等）。您只能在while的第一个循环中添加这些字段（在$user[id]已设置之后）。 skill和proficiency的值会在每个循环中添加到子数组$user[prg]。因此，当您输出表时，您将处理单个数组而不是多行，并且您将循环限制为$user[prg]子数组。

替代：

另一种方法是在MySQL查询中使用GROUP_CONCAT。

Answer 2

这样做：

<?php 

$result = $mysqli->query("SELECT tblstudent.studentId,tblstudent.programme,tblstudent.cgpa,tblpersonalinfo.studentId,tblpersonalinfo.pImage,tblpersonalinfo.pImageType,tblpersonalinfo.pImageSize,tblpersonalinfo.pName,tblskill.skill FROM tblstudent INNER JOIN tblpersonalinfo ON tblstudent.studentId = tblpersonalinfo.studentId INNER JOIN tblskill ON tblpersonalinfo.studentId = tblskill.studentId ".$where_sql."  ");

if ($result->num_rows != 0) {

    echo "<table class='scroll' width='700' border='0' bgcolor='#FF00FF' align='left'>";
    echo "<tbody>";
    $flag = true;
    while($row = mysqli_fetch_array($result)) {
         // get data from db
        if($flag){

            echo "<input type='hidden' name='id' value='".$row[0]."'>";
            echo "<tr>";
            echo "<td>";
            echo '<div  class="title bg-primary" align="left" style="font-weight: bold;">' .   '&nbsp;' . '<img src="uploads/' . $row['pImage'] .' " alt = "avatar" height="60" width="50" >' . '&nbsp;' . $row['pName'] .  '</div>';
            echo '<div  align="left" class="sub">' . '<br>' . $row['programme']. '</div>';


            echo "<table class='scroll' width='700' border='1' bgcolor='#FF00FF' align='left'>";
            echo "<tbody>";
            $flag=false;
        }
        echo "<tr>";
        echo "<td>";
        echo '<div  align="left" class="sub">' . '<br>' . $row['skill']. '</div>';
        echo "</td>";
        echo "</tr>";

    }
    echo "</tbody>";
    echo "</table>";
}
?>

您应该确保<tr></tr>循环中只重复while个代码。休息一切都应该只显示一次。

Answer 3

解决方案：

if ($result->num_rows != 0) {

    echo "<table class='scroll' width='700' border='0' bgcolor='#FF00FF' align='left'>";
    echo "<tbody>";

    $buffer = '';

    while($row = mysqli_fetch_array($result)) {

    // get data from db

    echo "<input type='hidden' name='id' value='".$row[0]."'>";
    echo "<tr>";
    echo "<td>";

    if($buffer != $row[0]){

        echo '<div  class="title bg-primary" align="left" style="font-weight: bold;">' .   '&nbsp;' . '<img src="uploads/' . $row['pImage'] .' " alt = "avatar" height="60" width="50" >' . '&nbsp;' . $row['pName'] .  '</div>';
        $buffer = $row[0];
    }

    echo '<div  align="left" class="sub">' . '<br>' . $row['programme']. '</div>';

    if ($row[0] == $row[0] ) {

        echo "<table class='scroll' width='700' border='1' bgcolor='#FF00FF' align='left'>";
        echo "<tbody>";
        echo "<tr>";
        echo "<td>";
        echo '<div  align="left" class="sub">' . '<br>' . $row['skill']. '</div>';
        echo "</td>";
        echo "</tr>";
        echo "</tbody>";
        echo "</table>";
        }
    }
}

在同一div标签中对具有相同ID的数据库进行分组

3 个答案:

说明：

替代：