我制作了这段代码,最终得到了一个包含2个数据帧的列表,以及一个内容错误的数据帧。
创建的DF看起来像这样:
DATE DEXDNUS DEXUSEU
2016-01-20 DEXDNUS nan
2016-01-21 DEXDNUS nan
2016-01-22 DEXDNUS nan
2014-12-04 nan DEXUSEU
2014-12-05 nan DEXUSEU
2014-12-08 nan DEXUSEU
但我需要的是实际的每日交易,而不仅仅是货币的符号......
像这样的东西
DATE DEXDNUS DEXUSEU
2014-12-04 6.78 1.24
2014-12-05 6.86 1.23
2014-12-08 6.81 1.27
我该怎么做?
import pandas as pd
import pandas.io.data as web
import datetime
xratelist = ['DEXDNUS', 'DEXUSEU']
xrts = []
def xRateList_pd(xratelist, modus='trading',start=datetime.datetime(2000,1,1),end=pd.Timestamp.utcnow()):
years = 1.2
days = int(252 * years) # ant. arb. dage pr år = 252
if modus == 'trading':
end = pd.Timestamp.utcnow()
start = end - days * pd.tseries.offsets.BDay()
print('Fetching xratelist from Fred: ', xratelist)
for xrt in xratelist:
r = web.DataReader(xrt, 'fred',
start = start, end = end)
# add a symbol column
r[xrt] = xrt
xrts.append(r)
# concatenate all the dfs into one
df_xrates = pd.concat(xrts)
return df_xrates
if __name__ == '__main__':
df_xrates = xRateList_pd(xratelist, modus='trading')
答案 0 :(得分:0)
如果我理解正确,您只需要在axis=1
电话中添加concat
:
df_xrates = pd.concat(xrts,axis=1)
这能否为您提供所追求的目标?
答案 1 :(得分:0)
如果您不想要符号列,请删除此部分:
function AppViewModel(listValues) {
this.tempArray = [];
this.listValues = ["Arnold","Bnolg","Cold"];
this.myArray = ko.observableArray();
this.searchValue = ko.observable();
this.myArray=this.listValues;
var self =this;
this.check = function(){
self.myArray=[];
for(var i=0;i<this.listValues.length;i++){
var kill = this.searchValue();
if(this.listValues[i].indexOf(kill) > -1){
this.tempArray.push(this.listValues[i]);
}
}
this.myArray=this.tempArray;
};
}
ko.applyBindings(new AppViewModel);
如果你想沿着列轴连接,请将# add a symbol column
r[xrt] = xrt
传递给axis='columns'
:
concat()