我在多个goroutine之间共享一个Golang结构。 对于结构成员的并发访问,有互斥锁sync.RWMutex。 对于由单个goroutine访问的struct成员,是否需要互斥保护?
例如,在下面的代码中,一个单独的writer goroutine访问成员shared.exclusiveCounter,没有任何锁定保护。这是正确/安全吗?或者是否需要互斥锁,因为整个结构由多个goroutines通过共享指针访问?
package main
import (
"fmt"
"sync"
"time"
)
func main() {
s := &shared{mutex: &sync.RWMutex{}}
readerDone := make(chan int)
writerDone := make(chan int)
go reader(s, readerDone)
go writer(s, writerDone)
<-readerDone
<-writerDone
}
type shared struct {
mutex *sync.RWMutex
sharedCounter int // member shared between multiple goroutines, protected by mutex
exclusiveCounter int // member exclusive of one goroutine -- is mutex needed?
}
func (s *shared) readCounter() int {
defer s.mutex.RUnlock()
s.mutex.RLock()
return s.sharedCounter
}
func (s *shared) setCounter(i int) {
defer s.mutex.Unlock()
s.mutex.Lock()
s.sharedCounter = i
}
func reader(s *shared, done chan<- int) {
for {
time.Sleep(2 * time.Second)
counter := s.readCounter()
fmt.Printf("reader: read counter=%d\n", counter)
if counter > 5 {
break
}
}
fmt.Printf("reader: exiting\n")
done <- 1
}
func writer(s *shared, done chan<- int) {
s.exclusiveCounter = 0
for {
time.Sleep(1 * time.Second)
s.exclusiveCounter++
fmt.Printf("writer: writing counter=%d\n", s.exclusiveCounter)
s.setCounter(s.exclusiveCounter)
if s.exclusiveCounter > 5 {
break
}
}
fmt.Printf("writer: exiting\n")
done <- 1
}
答案 0 :(得分:4)
如果只有一个goroutine访问struct成员,则不需要使用互斥锁来控制访问。我可能会使用一个(或者重新使用结构中的现有互斥锁,或者另一个),因为虽然今天可能只有一个goroutine访问该结构成员,但没有任何强制执行。
答案 1 :(得分:2)
你不需要另外一个互斥锁,如果你只是在int *类型上运行,你可以放弃互斥锁并使用atomic.*
type shared struct {
sharedCounter int64 // member shared between multiple goroutines, protected by mutex
exclusiveCounter int64 // member exclusive of one goroutine -- is mutex needed?
}
func (s *shared) readCounter() int64 {
return atomic.LoadInt64(&s.sharedCounter)
}
func (s *shared) setCounter(i int64) {
atomic.StoreInt64(&s.sharedCounter, i)
}